H - Se (two dots on top and two dots on bottom) - H Se has two lone pairs (a total of four dots) and a Hydrogen is bonded to either side of it.
The correct Lewis structure for selenium (Se) would have 6 valence electrons represented by the symbol "Se" surrounded by 6 dots or lines (representing valence electrons), giving a total of 12 electrons in the structure.
Since Selenium is in the same column as Oxygen and Sulfur, you would expect it to bond just like them. As a halogen, chlorine wants to make one bond so your final answer would be. Cl-Se-Cl with two lone pairs (that's 4 electrons) on selenium and 3 lone pairs (that's six electrons) on EACH chlorine.
The correct Lewis structure for carbononitridic chloride, CClN, includes a central carbon atom bonded to a nitrogen atom and a chlorine atom, with a single bond between each atom. The carbon atom has two lone pairs of electrons.
The Lewis theory states that atoms form bonds by sharing electrons. Strontium (Sr) is in group 2 and would lose 2 electrons, while selenium (Se) is in group 16 and would gain 2 electrons to achieve a stable octet. Therefore, SrSe2 would be the formula of the compound that forms between strontium and selenium.
The Lewis dot structure for SeTe3 will have selenium (Se) in the center bonded to three tellurium (Te) atoms. Each Te atom will be bonded to the Se atom by a single bond, and there will be lone pairs on the tellurium atoms to satisfy their octet.
H - Se (two dots on top and two dots on bottom) - H Se has two lone pairs (a total of four dots) and a Hydrogen is bonded to either side of it.
The chemical formula for aluminum selenide is Al2Se3. This is an ionic compound, so it is shown with 2 Al 2+ + 3 [Se] 2-. Around the Se are dot pairs on all four sides showing the complete transfer of electrons from the Al to the Se atoms.
If you go to your preferred search engine and search for "lewis dot of Se" you will find it. This is the best I can make on this form....Se:.
.. .. .. :O = Se - O: '' This bond contains a total of 18 electrons which is 9 pairs. In this structure, each element follows the octet rule.
The Lewis structure for hydrogen sulfide (H2S) consists of two hydrogen atoms bonded to a central sulfur atom. Sulfur has 6 valence electrons, hydrogen has 1 valence electron each, totaling 8 valence electrons in the molecule. There are two lone pairs on the sulfur atom and the hydrogen atoms are bonded to the sulfur atom.
.. .. .. :Cl - Se - Cl: .. .. .. There are two dots above the Cl, Se, and other Cl. There are also two dots below the Cl, Se, and other Cl. There are two dots to the left of Cl, and two dots to the right of the other Cl. The dash (-) represents two dots. So, there are a total of 20 electrons. Se has 6, and each chlorine has 7. 6 + 7(2) = 20
The correct Lewis structure for selenium (Se) would have 6 valence electrons represented by the symbol "Se" surrounded by 6 dots or lines (representing valence electrons), giving a total of 12 electrons in the structure.
Since Selenium is in the same column as Oxygen and Sulfur, you would expect it to bond just like them. As a halogen, chlorine wants to make one bond so your final answer would be. Cl-Se-Cl with two lone pairs (that's 4 electrons) on selenium and 3 lone pairs (that's six electrons) on EACH chlorine.
The correct Lewis structure for carbononitridic chloride, CClN, includes a central carbon atom bonded to a nitrogen atom and a chlorine atom, with a single bond between each atom. The carbon atom has two lone pairs of electrons.
The answer about SE is: symbol equation
Atomic mass Se = 78.96. So, atoms Se in 80.7g would be 80.7 g x 1mol/78.96g x 6.02x10^23atoms/mol = 6.15x10^23 atoms