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The mass of 3.2 moles O2? The atoms in 3.2 moles O2 Could be other things, I guess, but I will do these two.
3.2 moles O2 (32 grams/1 mole O2)
= 102.4 grams of gaseous oxygen
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3.2 mole O2 (6.022 X 1023/1 mole O2)
= 1.9 X 1024 atoms of gaseous oxygen
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What else can I help you with?
How many moles are in 64 g of oxygen?
4.80 grams O2 (1 mole O2/32 grams ) = 0.150 moles of O2
How many moles of H2O are product from reaction of 355 g of O2?
Balanced equation. 2H2 + O2 -> 2H2O 355 grams O2/32 grams = 11.1 moles O2 check for limiting reactant 11.1 moles O2 (2 mole H2/1 mole O2) = 22.2 mole H2 and H2 has no where near that many moles, so limits and drives reaction so, as they are one to one...... 22.2 moles of H2O are produced
How many grams of 02(g) are needed to completely burn 23.7 g of C38H(g)?
The balanced equation is C3H8 + 5O2 ---> 3CO2 + 4H2O moles C3H8 = 23.7 g x 1 mol/44 g = 0.539 moles moles O2 needed = 5 x 0.539 moles = 2.695 moles O2 (it takes 5 moles O2 per mole C3H8) grams O2 needed = 2.695 moles x 32 g/mole = 86.2 grams O2 needed (3 sig figs)
How many grams of o2 are required to produce 90g of no?
2 moles of nitrogen monoxide (NO) are produced from 1 mole of oxygen (O2) according to the balanced chemical equation 2NO = N2 + O2. One mole of NO has a molar mass of 30 g, so 90 g of NO corresponds to 3 moles of NO. Therefore, 3 moles of O2 are required to produce 90 g of NO, which is equivalent to (3 moles) x (32 g/mol) = 96 g of O2.
How many moles of O2 are required to produce 107.9 moles of FE2O3?
The balanced chemical equation for the formation of iron(III) oxide (Fe2O3) from iron (Fe) and oxygen (O2) is: 4 Fe + 3 O2 → 2 Fe2O3. From the equation, it can be seen that 3 moles of O2 are required to produce 2 moles of Fe2O3. Therefore, to produce 107.9 moles of Fe2O3, you would need (107.9 moles Fe2O3) × (3 moles O2 / 2 moles Fe2O3) = 161.85 moles of O2.
How many grams of O2 are in 15 moles of O2. with work shown?
15 moles O2 (32 grams/1 mole O2) = 480 grams
What is the number of moles in 32 grams of O2?
There are 1.0001 moles.
How many moles are in 64 g of oxygen?
4.80 grams O2 (1 mole O2/32 grams ) = 0.150 moles of O2
What mass of oxygen two moles of O2 molecules have molor mass of O2 is 32 grms per mole?
Two moles of O2 molecules would have a mass of 64 grams (2 moles x 32 grams/mole = 64 grams).
How many grams are there in 2.047 moles of O2?
For this you need the atomic (molecular) mass of O2. Take the number of moles and multiply it by the atomic mass. Divide by one mole for units to cancel.2.047 moles O2 × (32.0 grams) = 65.5 grams O2
How many moles in 150.0 g O2?
To find the number of moles in 150.0 g of O2, first calculate the molar mass of O2, which is 32.0 g/mol (16 g/mol for each oxygen atom). Then, divide the given mass by the molar mass to get the number of moles: 150.0 g / 32.0 g/mol = 4.69 moles of O2.
How you calculate the mass of 1.5 moles of oxygen molecule?
To calculate the mass of 1.5 moles of oxygen molecules (O2), you multiply the number of moles (1.5) by the molar mass of oxygen (O2). The molar mass of O2 is approximately 32 g/mol. So, the mass of 1.5 moles of oxygen molecules would be 1.5 moles * 32 g/mol = 48 grams.
How many grams of oxygen are formed when 6.21 moles of KOH are formed 4KO plus 2H2O equals 4KOH plus O2?
From the balanced chemical equation, 4 moles of KOH produce 1 mole of O2. Given that there are 6.21 moles of KOH, we can set up a ratio: (6.21 moles KOH) x (1 mole O2 / 4 moles KOH) = 1.5525 moles O2. Finally, using molar mass of oxygen (O2) which is 32 g/mol, we find that 1.5525 moles of O2 is equal to 49.68 grams of O2.
4NH3 7O2 4NO2 6H2O how many grams of oxygen are necessary to produce 4.50 moles of NO2?
To determine the grams of oxygen needed to produce 4.50 moles of NO2, use the coefficients in the balanced equation. In this case, 7 moles of O2 are required to produce 4 moles of NO2. Calculate: (4.50 moles of NO2) * (7 moles of O2 / 4 moles of NO2) = 7.88 moles of O2. Finally, convert moles to grams using the molar mass of O2 (32.00 g/mol): 7.88 moles * 32.00 g/mol = 252.16 grams of O2.
How many moles of oxygen are represent in 0.16 g of oxygen gas?
To find the number of moles of oxygen in 0.16 g of oxygen gas, you first need to determine the molar mass of oxygen (O2), which is about 32 g/mol. Then, you can use the formula moles = mass / molar mass to calculate the number of moles. In this case, 0.16 g / 32 g/mol = 0.005 moles of oxygen gas.
The number of molecules in 48.0 grams of oxygen gas (O2) is?
To find the number of molecules in 48.0 grams of oxygen gas (O2), you first need to determine the number of moles of O2 using its molar mass (32 g/mol). Then, you can use Avogadro's number (6.022 x 10^23 molecules/mol) to convert moles to molecules. The calculation would be: 48.0 g / 32 g/mol = 1.5 moles of O2, and 1.5 moles x 6.022 x 10^23 molecules/mol = 9.033 x 10^23 molecules of O2.
How many moles of H2O are product from reaction of 355 g of O2?
Balanced equation. 2H2 + O2 -> 2H2O 355 grams O2/32 grams = 11.1 moles O2 check for limiting reactant 11.1 moles O2 (2 mole H2/1 mole O2) = 22.2 mole H2 and H2 has no where near that many moles, so limits and drives reaction so, as they are one to one...... 22.2 moles of H2O are produced
