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What is the total no of valence electrons in 4.2 g of N3- ion is?
To determine the total number of valence electrons in 4.2 g of the N³⁻ ion, first calculate the number of moles of N³⁻ in that mass. The molar mass of nitrogen (N) is approximately 14 g/mol, so N³⁻ has a total of 5 valence electrons (as nitrogen has 5 valence electrons and gains 3 more to form the ion). In 4.2 g of nitrogen, there are about 0.3 moles, which corresponds to approximately 0.3 moles × 3 nitrogen atoms per ion × 5 valence electrons = 4.5 valence electrons in total.
What mass of protons would be required to just neutralize the charge of 4.4 g of electrons?
To find the mass of protons needed to neutralize the charge of 4.4 g of electrons, we first calculate the number of electrons in that mass. The charge of one electron is approximately (1.6 \times 10^{-19}) coulombs, and the mass of one electron is about (9.11 \times 10^{-31}) kg. Thus, 4.4 g of electrons corresponds to approximately (4.84 \times 10^{22}) electrons, which would require an equal number of protons to neutralize the charge. Since the mass of a proton is about (1.67 \times 10^{-27}) kg, the mass of protons needed would be approximately (8.06 \times 10^{-5}) kg, or 0.0806 g.
What does G mean on the periodic table?
"G" on the periodic table typically refers to the group number of elements, indicating the number of valence electrons an element has. For example, group 1 elements have 1 valence electron, group 2 elements have 2 valence electrons, and so on.
How much charge is present on 500 mg of electrons?
To calculate the charge on 500 mg of electrons, we first convert the mass to grams: 500 mg = 0.5 g. The number of moles of electrons can be found using the molar mass of electrons, which is approximately 0.00054858 g/mol. Therefore, 0.5 g corresponds to about 910 moles of electrons. Since each electron has a charge of approximately -1.602 x 10^-19 coulombs, the total charge is about -1.46 x 10^21 coulombs.
What is the mass of 2.6 g of magnesium and 1.6 g of oxygen?
The molar mass of magnesium is 24.31 g/mol, while the molar mass of oxygen is 16 g/mol. To find the mass of 2.6 g of magnesium, you can divide 2.6 g by the molar mass of magnesium (24.31 g/mol) and multiply by Avogadro's number to find the number of moles. Similarly, you can do the same calculation for 1.6 g of oxygen and then sum up the molar masses to find the total mass.
What are the lyrics to hot cross buns?
hot cross buns, hot cross buns, one a penny, two a penny, three a penny, four a penny, five a penny, six a penny, seven a penny, eight a penny, nine a penny, ten a penny, hot cross buns.Hot cross buns! Hot cross buns!One a penny, two a pennyHot cross buns!If you have no daughters, give them to your sons!One a penny, two a pennyHot cross buns!
What mass of protons would be required to just neutralize the charge of 4.4 g of electrons?
To find the mass of protons needed to neutralize the charge of 4.4 g of electrons, we first calculate the number of electrons in that mass. The charge of one electron is approximately (1.6 \times 10^{-19}) coulombs, and the mass of one electron is about (9.11 \times 10^{-31}) kg. Thus, 4.4 g of electrons corresponds to approximately (4.84 \times 10^{22}) electrons, which would require an equal number of protons to neutralize the charge. Since the mass of a proton is about (1.67 \times 10^{-27}) kg, the mass of protons needed would be approximately (8.06 \times 10^{-5}) kg, or 0.0806 g.
How many electrons in 2.9 grams of copper?
i havent got an elements table in front of me but here is how you do it: figure out how many moles is 2.9 grams of copper by using molecular wieght, then simply multiply so: No of moles* No of atoms in one mole* number of electrons in one atom of copper (which is the same as the No of protons...)
What does G mean on the periodic table?
"G" on the periodic table typically refers to the group number of elements, indicating the number of valence electrons an element has. For example, group 1 elements have 1 valence electron, group 2 elements have 2 valence electrons, and so on.
What is the number of moles in 12.0 g of phosphorus?
To find the number of moles in 12.0 g of phosphorus, first find the molar mass of phosphorus, which is about 31.0 g/mol. Then, divide the given mass by the molar mass to get the number of moles: 12.0 g / 31.0 g/mol ≈ 0.387 moles.
How many electrons are lost by 42 g of sodium when its atom are oxidized to ions?
The ion sodium is Na + so we have a one to one loss and can just find the atoms of sodium in the mass. 42 grams sodium (1 mole Na/22.99 grams)(6.022 X 1023/1 mole Na) = 1.1 X 1024 atoms of sodium -----------------------------------------now, Every atom of sodium donates one electron to become a sodium ion. So. We have.....1.1 X 1024 .......electrons lost by 42 grams of sodium ionized.
How much does a 2008 penny weight?
2.5 g
What is the maximum number of electrons that can occupy 5d subshells?
In any shell excluding shell1, there is only 1 s orbital and 1 p orbital. Subshells and the Orbitals are same. Orbital g is known as subshell 5. g orbital is present shell 6. But till today no element is discovered with an electron in g orbital.
What is the diameter of a penny in millimeter and its mass in grams?
English penny of today: 3,56 g and 20,32 mm.
Where can you find a solution to problem solving number of moles in a given element?
Number of moles = Mass of the sample in g/Molar mass in g
How many moles of SO2 are present in 250.0 g?
Number of moles is determined by dividing molar mass into the number of grams. SO2 has a molar mass of 64.066 g. To find the number of moles in 250.0 g of SO2, divide 250.0 g by 64.066 g. This gives you just over 3.9 moles.
How many electrons are in 9 g of carbon 13?
Since carbon 13 is an isotope of carbon with a mass number of 13, it has 13 nucleons (protons and neutrons). The number of electrons in a neutral carbon 13 atom is equal to the number of protons in its nucleus, which is 6. Therefore, in 9 g of carbon 13, there are Avogadro's number of carbon 13 atoms, each with 6 electrons, totaling approximately 3 x 10^23 electrons.
