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How many atoms are in 5.22 g of phosporous?
To find the number of atoms in 5.22 g of phosphorus, you first need to determine the number of moles of phosphorus by dividing the given mass by the molar mass of phosphorus (31.0 g/mol). From there, you can use Avogadro's number (6.022 x 10^23 atoms/mol) to convert moles to atoms.
What is the empirical formula of a phosphoric acid that contains 0.3086 g of hydrogen 3.161 g of phosphorus and 6.531 g of oxygen?
moles H = 0.3086 H x 1 mol/1 g = 0.3086 moles Hmoles P = 3.161 g x 1 mol/31 g = 0.101 moles Pmoles O = 6.541 g x 1 mol/16 g = 0.41 moles Odivide all by 0.101 to get 3.0 moles H, 1 mole P and 4 moles OEmpirical formula = H3PO4
How many phosphorus atoms are contained in 158 kg of phosphorus?
To calculate the number of phosphorus atoms in 158 kg of phosphorus, we first need to determine the number of moles of phosphorus in 158 kg using the molar mass of phosphorus. Then we can use Avogadro's number (6.022 x 10^23 atoms per mole) to convert moles of phosphorus to atoms. The final calculation will give us the total number of phosphorus atoms in 158 kg.
What is the number of moles of argon in 607 g of argon?
the equation is Xg multiplied by the moles/grams of X = moles of X (the grams cancel leaving you with moles) 607g Ar x 1 mole/ 39.95g = 15.19 moles
How many moles of SO2 are present in 250.0 g?
Number of moles is determined by dividing molar mass into the number of grams. SO2 has a molar mass of 64.066 g. To find the number of moles in 250.0 g of SO2, divide 250.0 g by 64.066 g. This gives you just over 3.9 moles.
How many moles of phosphorus atoms are in a 100 g sample of phosphorus?
The gram atomic mass of phosphorus is 30.9738, and by definition, a mole of such atoms contains Avogadro's Number of atoms. Therefore, 100 g of phosphorus contains 100/30.9738 or 3.23 moles, to the justified number of significant digits.
2. Calculate the number of moles of phosphorus in 15.95 g of tetraphosphorus decaoxide.?
To calculate the number of moles of phosphorus in 15.95 g of tetraphosphorus decaoxide (P₄O₁₀), first determine its molar mass. The molar mass of P₄O₁₀ is approximately 284 g/mol (4 phosphorus atoms at 31 g/mol each and 10 oxygen atoms at 16 g/mol each). Next, use the formula: moles = mass (g) / molar mass (g/mol). So, moles of P₄O₁₀ = 15.95 g / 284 g/mol ≈ 0.0562 moles. Since there are 4 moles of phosphorus in each mole of P₄O₁₀, multiply by 4 to find the moles of phosphorus: 0.0562 moles × 4 ≈ 0.2248 moles of phosphorus.
How many moles of phosphorus?
The number of moles of phosphorus depends on the given quantity or mass of phosphorus. To calculate the number of moles, you need to know the molar mass of phosphorus (about 30.97 g/mol) and the mass of the sample. You can then use the formula moles = mass/molar mass to find the number of moles.
How many atoms are in 5.22 g of phosporous?
To find the number of atoms in 5.22 g of phosphorus, you first need to determine the number of moles of phosphorus by dividing the given mass by the molar mass of phosphorus (31.0 g/mol). From there, you can use Avogadro's number (6.022 x 10^23 atoms/mol) to convert moles to atoms.
How many moles of phosphorus atoms are in 100 grams of P4S10?
To find the number of moles of phosphorus atoms in 100 grams of P4S10, we first need to determine the molar mass of P4S10 which is 284.26 g/mol. Next, we calculate the number of moles of P4S10 in 100 grams by dividing 100 g by the molar mass to get 0.352 moles of P4S10. Since there are 4 phosphorus atoms in each P4S10 molecule, there are 0.352 moles x 4 = 1.41 moles of phosphorus atoms in 100 grams of P4S10.
What is the empirical formula of a phosphoric acid that contains 0.3086 g of hydrogen 3.161 g of phosphorus and 6.531 g of oxygen?
moles H = 0.3086 H x 1 mol/1 g = 0.3086 moles Hmoles P = 3.161 g x 1 mol/31 g = 0.101 moles Pmoles O = 6.541 g x 1 mol/16 g = 0.41 moles Odivide all by 0.101 to get 3.0 moles H, 1 mole P and 4 moles OEmpirical formula = H3PO4
How many grams of phosphorus trichloride are present in 3.42 moles of this compound?
3,42 moles of phosphorus trichloride have 469,6686 g.
How many moles in 2.3 grams of phosphorus?
mole = mass/molar mass mass=2.3 grams molar mass=30.97 2.3/30.97=0.0742 moles
How many moles of sodium hydroxide are found in 120 grams of Na OH?
The mole of a metal, such as sodium, is generally assumed to consist of Avogadro's Number of single atoms. The gram atomic mass of sodium is 22.9898. The number of moles in 120 grams of Na is therefore 120/22.9898, or 5.22, rounded to the justified number of significant digits.
How many grams of phosphorus are present in 4.70 moles of tetraphosphorus decaoxide?
4,70 moles of tetraphosphorus decaoxide contain 582,56 g phosphorus.
How many atoms in 5.18 g P?
To find the number of atoms in 5.18 grams of phosphorus (P), first determine the molar mass of phosphorus, which is approximately 30.97 g/mol. Then, calculate the number of moles in 5.18 g by dividing the mass by the molar mass: 5.18 g / 30.97 g/mol ≈ 0.167 moles. Finally, multiply the number of moles by Avogadro's number (approximately (6.022 \times 10^{23}) atoms/mol) to find the number of atoms: 0.167 moles × (6.022 \times 10^{23}) atoms/mol ≈ (1.01 \times 10^{23}) atoms.
How many moles of calcium represent in 120 grams?
120 g calcium is equal to 3 moles.
