One mole of oxygen is 32 g.
The answer is: 5 moles oxygen and 4 moles H2O.The reaction is:C3H8 + 5 O2 = 3 CO2 + 4 H2O
2Mg + O2 -----> 2MgO So two moles of magnesium oxide are formed if x moles of magnesium are allowed to react with only 1 mole of oxygen molecules. The oxygen has become the limiting ingredient.
16 grams of oxygen how many moles is 0,5 moles.
The nunber of moles of oxygen is 2,5.
The formula means, among other things, that there are 7 atoms of oxygen in each mole of the compound. Therefore, in 4.00 moles of the compound, there are 28.00 moles of oxygen atoms. Elemental oxygen usually is diatomic, so that there would be the equivalent of 14 moles of diatomic elemental oxygen.
Only when 5.5 mole O2 react with 11 mole H2, then 11 mole H2O are formed.
To calculate the amount of CO formed from 35.0 grams of oxygen, you need to determine the limiting reactant. First, convert 35.0 grams of O2 to moles. Then, use the balanced equation to calculate the moles of CO that can be formed from the moles of O2. Finally, convert the moles of CO to grams using the molar mass of CO.
The amount of water formed from a reactionof hydrogen and oxygen conforms to the chemical equation: 2H2 + O2 --> 2H2O For every two moles of hydrogen which reacts with one mole of oxygen, 2 moles of water are formed.
To determine the grams of potassium chloride formed, you first need to calculate the moles of oxygen produced by the decomposition of potassium chlorate. Then, use the stoichiometry of the balanced chemical equation to convert moles of oxygen to moles of potassium chloride. Finally, from the molar mass of potassium chloride, you can calculate the grams formed.
The answer is: 5 moles oxygen and 4 moles H2O.The reaction is:C3H8 + 5 O2 = 3 CO2 + 4 H2O
To determine the moles of CO2 formed when 58 g of butane burns in oxygen, first, calculate the moles of butane using its molar mass. Then, use the stoichiometry of the balanced chemical equation to find the moles of CO2 formed, as per the ratio of the coefficients in the balanced equation.
2Mg + O2 -----> 2MgO So two moles of magnesium oxide are formed if x moles of magnesium are allowed to react with only 1 mole of oxygen molecules. The oxygen has become the limiting ingredient.
The most straightforward reaction for the formation of SO3 from SO2 is 2 SO2 + O2 => 2 SO3. If this is the actual reaction for the formation, 3 moles of SO3 are formed from 3 moles of SO2.
3,7 moles of C8H11NO2 have 3,7 moles of oxygen (O2).
2H2 + O2 --> 2H2OAs you can see by the balanced reaction, for every 1 mole of oxygen used, 2 moles of water are formed. Also notice that for every 1 mole of oxygen used, you need 2 moles of hydrogen to produce the 2 moles of water. So in your case 110 moles of oxygen would produce 220 moles of water & would also require 220 moles of hydrogen (which you have in excess since you have 230 moles of hydrogen). So 220 moles of water are the most that can be formed.
16 grams of oxygen how many moles is 0,5 moles.
12 moles KClO3 (3 moles O/1 mole KClO3) = 36 moles of oxygen.