In what container can you transport acetone to South america?
Yes, mainly there are 3 types of acetone: regular acetone, acetone with enriched formula, maximum strength acetone.
To find the volume of acetone, we need to know its density. The density of acetone is around 0.79 g/cm^3. Using the formula Volume = Mass / Density, the volume of 85.1g of acetone would be 107.84 cm^3.
Acetone is used in acetylene tanks to absorb and stabilize acetylene gas. It acts as a solvent that helps dissolve acetylene, allowing for safer storage at higher pressures. By absorbing acetylene, acetone prevents the gas from becoming too concentrated, which could lead to instability or detonation. This combination helps ensure the safe handling and transport of acetylene.
Assuming the density of acetone is 0.79 g/ml, and the molar mass of acetone is 58.08 g/mol, you can calculate the number of acetone molecules in 330 ml using Avogadro's number. This will give you approximately 6.69 x 10^23 molecules of acetone in a 330 ml bottle of acetone.
No acetone is an organic ketone solvent.
Hazard Class 3
In terms of chemical class, acetone is a ketone and, more broadly, an organic chemical. In terms of hazard classification, acetone is a Class 3 Flammable Liquid
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In addition to a class label and UN number, a package containing acetone must display the proper shipping name, which includes "Acetone," and any relevant hazard symbols or pictograms that indicate flammability. Additionally, the package should contain handling instructions and any required precautionary statements to ensure safe transport and handling.
Yes, mainly there are 3 types of acetone: regular acetone, acetone with enriched formula, maximum strength acetone.
To 3
Density of acetone (liquid) is 0.7845 g cm−3 (25 °C)
acetone does not react with potassium dichromate
The density of acetone at 23°C is approximately 0.7845 g/cm^3.
To find the volume of acetone, we need to know its density. The density of acetone is around 0.79 g/cm^3. Using the formula Volume = Mass / Density, the volume of 85.1g of acetone would be 107.84 cm^3.
No, because when you add acetone to acetone, all you are doing is adding more of the volume of acetone to acetone. You are just changing the amount of acetone, not anything chemically happening.
To calculate the percent by mass of carbon in acetone (C3H6O), first calculate the molar mass of carbon in acetone: 3(C) = 3(12.01 g/mol) = 36.03 g/mol. Then calculate the molar mass of acetone: (3(12.01 g/mol) + 6(1.01 g/mol) + 16.00 g/mol = 58.08 g/mol. Finally, divide the molar mass of carbon by the molar mass of acetone and multiply by 100 to get the percent by mass of carbon in acetone: (36.03 g/mol / 58.08 g/mol) x 100 ≈ 62.07%.