In what container can you transport acetone to South america?
Yes, mainly there are 3 types of acetone: regular acetone, acetone with enriched formula, maximum strength acetone.
To find the volume of acetone, we need to know its density. The density of acetone is around 0.79 g/cm^3. Using the formula Volume = Mass / Density, the volume of 85.1g of acetone would be 107.84 cm^3.
Acetone is used in acetylene tanks to absorb and stabilize acetylene gas. It acts as a solvent that helps dissolve acetylene, allowing for safer storage at higher pressures. By absorbing acetylene, acetone prevents the gas from becoming too concentrated, which could lead to instability or detonation. This combination helps ensure the safe handling and transport of acetylene.
No acetone is an organic ketone solvent.
Assuming the density of acetone is 0.79 g/ml, and the molar mass of acetone is 58.08 g/mol, you can calculate the number of acetone molecules in 330 ml using Avogadro's number. This will give you approximately 6.69 x 10^23 molecules of acetone in a 330 ml bottle of acetone.
Hazard Class 3
In terms of chemical class, acetone is a ketone and, more broadly, an organic chemical. In terms of hazard classification, acetone is a Class 3 Flammable Liquid
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Yes, mainly there are 3 types of acetone: regular acetone, acetone with enriched formula, maximum strength acetone.
To 3
Density of acetone (liquid) is 0.7845 g cm−3 (25 °C)
acetone does not react with potassium dichromate
The density of acetone at 23°C is approximately 0.7845 g/cm^3.
To find the volume of acetone, we need to know its density. The density of acetone is around 0.79 g/cm^3. Using the formula Volume = Mass / Density, the volume of 85.1g of acetone would be 107.84 cm^3.
No, because when you add acetone to acetone, all you are doing is adding more of the volume of acetone to acetone. You are just changing the amount of acetone, not anything chemically happening.
Active Transport is carried out in our body cells. Active Transport uses energy to transport materials.
To calculate the percent by mass of carbon in acetone (C3H6O), first calculate the molar mass of carbon in acetone: 3(C) = 3(12.01 g/mol) = 36.03 g/mol. Then calculate the molar mass of acetone: (3(12.01 g/mol) + 6(1.01 g/mol) + 16.00 g/mol = 58.08 g/mol. Finally, divide the molar mass of carbon by the molar mass of acetone and multiply by 100 to get the percent by mass of carbon in acetone: (36.03 g/mol / 58.08 g/mol) x 100 ≈ 62.07%.