no
The hardness depends on the thermal and chemical treatment and is between 200 HB and 375 HB.
HB stands for "halfback" in football. The halfback is a running back position on the offensive team and is typically responsible for running with the ball and catching passes.
As I understand it, and very simplistically, I think it means that the bonding is easily reversible. In other words, the O2 is readily bound to haemoglobin but is also readily released depending on the partial saturation levels of Oxygen (PO2) that are encountered by the RBC. * In the pulmonary capillaries the PO2 is high and therefore the amount of O2 bound to Hb is also high (fully saturated). In the systemic capillaries the PO2 is low and hence the O2 dissociates with the Hb and diffuses into the tissue cells. (The Hb is then said to be partially saturated). Although PO2 is the major factor in the binding of O2 to Hb, other factors also effect this process. * Acidity: Lactic acid and carbonic acid generated during exercise lowers the pH of the blood which promotes the release of O2 from Hb. Hence the exercising tissues which require extra O2 help create a situation where more O2 is available. * PCO2 effects the transport and delivery of O2. Increased metabolic activity of the tissue cells produces more CO2 as waste, which promotes release of O2 from Hb through an associated decrease in pH (see above point) and also as part of an O2/CO2 cycle. It goes something like this: In the pulmonary capillaries, O2 diffuses from the alveolus into the RBC. It binds to Hb to create oxyhaemoglobin and H+ ions. Bicarbonate ions combine with the H+ ions to create carbonic acid which, under the influence of the enzyme carbonic anhydrase, dissociates into CO2 and water. The CO2 diffuses into the alveoli and is expelled by the lungs. The RBC then travels in the blood to the systemic capillaries and CO2 diffuses from the tissues (as a waste product of tissue cell metabolism) into the RBC. A small percentage of the CO2 binds to the globin in Hb, forming carbaminohaemoglobin, this causes O2 to dissociate from the haem part of the Hb. The O2 then diffuses from the RBC into the tissue cells. Most of the CO2, under the influence of the enzyme carbonic anhydrase, combines with H2O to become Carbonic acid which then dissociates into Bicarbonate ions (HCO3-) and H+ ions. The H+ ions promote the dissociation of O2 from the haemoglobin by taking the place of the O2 in the Hb molecule. * Increased temperature also has a minor effect of promoting the release of O2 from the Hb. Anatomy and physiology books such as "Anatomy and Physiology - From Science to Life" by Jenkins Kemnitz and Tortora is a fabulous resource for understanding the intricacies of this process.
The typical hardness values for C45 steel is around 167-229 HB, for ST52 it is around 201-255 HB, and for SAE4140 it is around 217-249 HB. Hardness values can vary depending on the specific heat treatment and processing of the material.
Yes, the Pentel Hi-Polymer 0.5 mm HB lead is suitable for use on standardized tests that require No. 2 pencils. The HB lead designation is equivalent to the No. 2 pencil standard, ensuring that it will be recognized by scanning machines.
The simplest type of acid-base reaction can be represented by the general equation: [ \text{HA} + \text{B} \rightarrow \text{A}^- + \text{HB}^+ ] In this equation, HA represents an acid that donates a proton (H⁺) to the base B, resulting in the formation of its conjugate base A⁻ and the conjugate acid HB⁺. This transfer of protons is the hallmark of Brønsted-Lowry acid-base theory.
Conjugate base B- is stronger, it has a higher pH at Eq.P.Your first (and also the original) question is answered as follows:At first one has to suppose that the concentrations of HA and HB are the same! 1)Eq.P. at pH=8: You need less OH- (titrant) to reach this, so the acid donated its last proton easier, so it was stronger. (Eq.P. at pH=7 means it isn't weak at all)1) It is more accurate to compare pH value's half-the-wayof titration, because pH1/2way is exactly equal to pKa value of the acid concerned AND it is independent of concentration: it is buffered!!!
An equation demonstrating Bronsted-Lowry acid-base properties can be written as HA + B -> A- + HB+, where HA is the acid donating a proton (H+), B is the base accepting the proton, A- is the conjugate base formed by the acid losing the proton, and HB+ is the conjugate acid formed by the base accepting the proton. This equation shows the transfer of a proton from an acid to a base, following the Bronsted-Lowry definition of acids and bases.
Suppose: B- is symbol for any (soluble) base.Equilibrium of a base when diluted in water:B- + H2O HB + OH-Equilibrium constant:Keq = [HB] * [OH-] / [B-] * [H2O]The base dissociation contant is defined by:KB = [HB]*[OH-]/[B-]So, KB = Keq*[H2O] = Keq*55.6 mol/L
dissociation of acid in water: A + H2O <-> A- + H3O+ with dissociation constant Ka = [A-][H3O+]/[A][H2O] = [A-][H3O+]/[A]. dissociation of base in water: B + H2O <-> HB+ + OH- with dissociation constant Kb = [HB+][OH-]/[B][H2O] = [HB+][OH-]/[B] dissociation of water in itself: 2H2O <-> H3O+ + OH- with dissociation constant Kw = [H3O+][OH-]/[H2O]^2 = [H3O+][OH-] where [H2O] has been ommitted because it is a pure liquid. substituting relations for Ka and Kb into Kw gives: Kw = [H3O+][OH-] = (Ka[A]/[A-])(Kb[B]/[HB+]) = KaKb where [A] = [HB+] and [B] = [A-].
In general it is said to be neutral, but having said so you can (and Mr. Lewis did in his theory on acid and base) see water as both an acid and as base:Acid behaviour of H2O, donating a proton to base B- H2O + B- --> OH- + HB (1)base behaviour of H2O, accepting a proton from acid HB H2O + HB --> H3O+ + B- (2)Ampholyte*) behaviour: donating a proton to itself as acceptor(H2O)donor + (H2O)acceptor OH- + H3O+which makes water having both concentrations [H3O+] = [OH-] = 1.0*10-7, so: pH = 7*) Ampholyt means: both donor and acceptor, at the same time, 'like twins'
It depends a bit on the buffer itself, but it is usually true. Generally speaking, a buffer is a solution composed of a weak acid (or base) along with its conjugate base (or acid). Usually, the two components (let's call the HA and A- for a weak acid and its conjugate base) are added in equal concentrations. If this is the case, then it is also true that the pH of the solution is equal to the pKa of the weak acid, a very useful fact. If the concentration of two HA and A- are equal, then the buffer capacity should be the same using a strong acid or strong base. However, you can also make a buffer with unequal concentrations of HA and A-. This is still considered a buffer solution, and it will resist change to pH in both directions, but unequally now. If you have a higher concentration of HA than A-, then the buffer will have a higher capacity to resist pH change if you add a strong base (because the base will be deprotonating HA, which you have more of). If you added a strong acid instead, then you would protonate all the A- faster (than you would deprotonate HA with the same amount of strong base), and so it would have a lower buffer capacity. This discussion works equally well if you are using a weak base (B) and its conjugate acid (HB+) instead, except everything is switched!
to convert the Hb to acid-hematin which is a brown coloured complex.
If a strong acid is mixed with a weak base, pH=pKa+/-1 in the buffer region.Corrected:If a strong base is mixed with a weak acid pOH= pKb +/-1 ( pH=(14 - pKb)+/-1) in the buffer region[Remember: For one conjugated pair of weak acid (a = HB) AND its weak base (b = B-):pKa + pKb = 14.0andpH + pOH = 14.0
HCl (hydrochloric acid) is used in the estimation of hemoglobin (Hb) because it helps to release hemoglobin from red blood cells, making it more accessible for measurement. It also helps to remove other interfering substances, ensuring a more accurate estimation of hemoglobin levels.
HB
In general it is said to be neutral, but having said so you can (and Mr. Lewis did in his theory on acid and base) see water as both an acid and as base:Acid behaviour of H2O, donating a proton to base B- H2O + B- --> OH- + HB (1)base behaviour of H2O, accepting a proton from acid HB H2O + HB --> H3O+ + B- (2)Ampholyte*) behaviour: donating a proton to itself as acceptor(H2O)donor + (H2O)acceptor OH- + H3O+which makes water having both concentrations [H3O+] = [OH-] = 1.0*10-7, so: pH = 7*) Ampholyt means: both donor and acceptor, at the same time, 'like twins'