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What else can I help you with?
Explain why the percent composition of certain compounds are not sufficient to determine the compounds molecular formulas?
Because unlike the empirical formula, the molecular formula does not have to be the simplest ratio.If by chance you are given the percent composition of the elements in a substance, you could calculate the empirical formula and then the empirical formula's mass. However, the molecular formula equation is molecular formula= (empirical formula)n, where n is the mass of the molecular formula divided by the mass of the empirical formula. You would, therefore, need to know the mass belonging to the molecular formula, which you are not given.
An unknown sample with a molecular mass of 180.0g is analyzed to yield 40 percent C 6.7 percent H and 53.3 percent O What is the empirical formula and the molecular formula of this compound?
The empirical formula is CH2O. To find the molecular formula, you need to calculate the empirical formula weight (30 g/mol) and divide the molecular mass (180.0 g/mol) by the empirical formula weight to get 6. This means the molecular formula is (CH2O)6, which simplifies to C6H12O6, the molecular formula of glucose.
Can the empirical formula be used to calculate the percent composition of a compound?
Yes, the empirical formula can be used to determine the percent composition of a compound. The percent composition can be calculated by determining the molar mass of each element in the formula and then dividing the molar mass of each element by the molar mass of the whole compound, and finally multiplying by 100 to get the percent composition.
What is the Empirical formula of the compound that is 52.7 percent K 47.3 percent Cl?
The empirical formula of the compound with 52.7% K and 47.3% Cl is KCl (potassium chloride). This is because the ratio of potassium to chlorine atoms in the compound is 1:1, leading to the simple formula KCl.
Can you Calculate the empirical formula of the compound made from 43.4 percent Na 11.3 percent C and 45.3 percent O by mass enter the empirical formula?
Firstly divide percentages by molar mass of that elementNa43.4/23=1.9C11.3/12.01=0.94O45.3/16=2.83Then divide the result of the first step by the smallest answerNa1.9/.94=2C.94/.94=1O2.83/.94=3Empirical Formula is Na2CO3
Can you determine the molecular formula of a substance from its percent composition?
Not completely. The empirical formula of a substance can be determined from its percent composition, but a determination of molecular weight is needed to decide which multiple of the empirical formula represents the molecular formula.
How can one determine the empirical formula from percent composition?
To determine the empirical formula from percent composition, first convert the percentages to grams. Then divide the grams of each element by its molar mass to find the moles. Finally, divide the moles of each element by the smallest number of moles to get the simplest whole number ratio, which represents the empirical formula.
How can one determine the empirical formula from mass percent composition?
To determine the empirical formula from mass percent composition, one must convert the mass percentages of each element in a compound into moles. Then, divide the moles of each element by the smallest number of moles to find the simplest whole number ratio of elements in the compound, which represents the empirical formula.
How can one determine the empirical formula from percent by mass?
To determine the empirical formula from percent by mass, first convert the percentages to grams. Then divide the grams of each element by its molar mass to find the moles. Next, divide the moles of each element by the smallest number of moles to get the simplest ratio. Finally, use this ratio to write the empirical formula.
Calculate the empirical formula of a compound formed from 3 percent C 0.3 percent H and 96.7 percent you Which formula below correctly represents the empirical formula?
Chi a+
Calculate the empirical formula of a compound formed from 3 percent c 3 percent h and 96 7 percent you which formula below correctly represents the empirical formula?
CHI3
Empirical formula of a compound containing 60.3 percent magnesium and 39.7 percent oxygen?
The empirical formula of this compound would be MgO.
A compound used to test for the presence of ozone in the stratosphere contains 96.2 percent thallium and 3.77 percent oxygen What is its empirical formula?
The molar mass of the compound is 444.8 g/mol. To find the empirical formula, we need to determine the number of moles of each element in the compound. The molar ratio of thallium to oxygen is approximately 3:1, so the empirical formula is TlO3.
How does one determine an empirical formula form a percent composition?
To determine the empirical formula from a percent composition, you must assume you have 100 g of the compound. Convert the percent composition into grams, then divide the mass of each element by its molar mass. Next, divide each result by the smallest number obtained, and round to the nearest whole number if necessary to find the ratio of elements. These whole numbers represent the subscripts in the empirical formula.
How do you know when to solve for a empirical formula?
You should solve for an empirical formula when you are given the percent composition of elements in a compound or when you have the molar mass of the compound but not the molecular formula. The empirical formula provides the simplest whole-number ratio of atoms in a compound.
If a compound containing chromium and silicon has 73.52 mass percent chromium what is its empirical formula?
To find the empirical formula, we need to determine the molar ratio of chromium to silicon. If 73.52% of the compound's mass is chromium, then the mass of silicon must be 100% - 73.52% = 26.48%. Next, we convert these percentages to moles, then divide by the smallest number of moles to get the simplest whole number ratio. The empirical formula is CrSi.
What is the percent composition of a compound with the empirical formula CO2?
The percent composition of a compound with the empirical formula CO2 is 27.3% carbon and 72.7% oxygen.
