It seems there might be a typo in your question, as both quantities appear identical: 0.50 mol of Na₂CO₃. If you meant to compare it to a different concentration or another substance, please clarify. However, if you are indeed referring to the same substance, then there is no difference between the two; both represent the same amount of sodium carbonate in moles.
The balanced equation for the reaction between MnSO4 and Na2CO3 is: MnSO4 + Na2CO3 -> MnCO3 + Na2SO4.
the chemical formula of washing soda is Na2CO3 (Sodium carbonate).
With great difficulty - since there is no x in Na2CO3.
First it's CaCl2, with a lowercase L, not an i. The balanced equation is: Na2CO3(aq) + CaCl2(aq) --> 2NaCl(aq) + CaCO3(s)
Washing soda is sodium carbonate, Na2CO3. Using the atomic weights from the periodic table and the subscripts in the formula, the molar mass of Na2CO3 = 106g/mol. 5g Na2CO3 x (1mol Na2CO3/106g/mol) = 0.05mol Na2CO3
difference between 0.50mol na2co3 anf 0.50 M of na2co3
0.50 mol of Na2CO3 represents a fixed quantity of the compound (50% of a mole), whereas 0.50M Na2CO3 indicates the concentration of Na2CO3 in a solution (0.50 moles per liter). The former is a measure of the amount of the substance, while the latter is a measure of its concentration in solution.
The balanced equation for the reaction between MnSO4 and Na2CO3 is: MnSO4 + Na2CO3 -> MnCO3 + Na2SO4.
the chemical formula of washing soda is Na2CO3 (Sodium carbonate).
With great difficulty - since there is no x in Na2CO3.
The balanced chemical equation for the reaction between Na2CO3 and CaCl2 to form CaCO3 and NaCl is: Na2CO3 + CaCl2 -> CaCO3 + 2NaCl. Therefore, the coefficients are 1, 1, 1, and 2 for Na2CO3, CaCl2, CaCO3, and NaCl respectively.
The chemical equation for sodium carbonate is Na2CO3. It is made up of two sodium atoms, one carbon atom, and three oxygen atoms. When dissolved in water, it dissociates into sodium ions (Na+) and carbonate ions (CO3^2-).
The chemical formula of sodium carbonate is Na2CO3.
The chemical symbol for sodium carbonate is Na2CO3.
The formula mass of sodium carbonate, Na2CO3 is 2(23.0) + 12.0 + 3(16.0) = 106.0Amount of Na2CO3 = mass of sample/molar mass = 0.75/106.0 = 0.00708mol There are 0.00708 moles of Na2CO3 in a 0.75g pure sample.
First it's CaCl2, with a lowercase L, not an i. The balanced equation is: Na2CO3(aq) + CaCl2(aq) --> 2NaCl(aq) + CaCO3(s)
yes