How many 02 molecules are needed to react with 5.35 grams of S?

Answer 1

The molar mass of sulfur (S) is approximately 32 g/mol. Therefore, 5.35 grams of S is equal to 5.35/32 = 0.167 moles of S. The balanced chemical equation for the reaction of sulfur with oxygen is given by 2S + 3O2 → 2SO3, which means 3 moles of O2 are needed to react with 2 moles of S. Hence, for 0.167 moles of S, we would need (3/2) * 0.167 = 0.2505 moles of O2, which is equivalent to 0.2505 * 6.022 x 10^23 = 1.51 x 10^22 molecules of O2.