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How many 100 gram tablets are needed to make 1 liter of a 25 percent of a solution?
To make a 25% solution, you need 250 grams of the solute for every 1 liter of solution. Since each tablet weighs 100 grams, you would need 250 grams ÷ 100 grams/tablet = 2.5 tablets. Therefore, you would need 3 tablets to ensure you have enough for a 25% solution, as you can't use a fraction of a tablet.
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If 5 liters of a 4 percent silver iodide solution must be mixed with a 10 percent solution to get a 6 percent solution How many liters of the 10 percent solution are needed?
Let x be the number of liters of the 10% solution needed. The amount of silver iodide in the 5-liter solution is 0.04 * 5 = 0.2 liters. The final amount of silver iodide in the mixture would be 5 * 0.06 = 0.3 liters. Set up the equation: 0.1x + 0.2 = 0.3, solve for x, x = 1 liter. Hence, 1 liter of the 10% solution is needed.
How you can convert 10 percent sugar solution in 5 percent sugar solution?
To convert a 10% sugar solution into a 5% sugar solution, you would need to dilute the original solution by adding a calculated amount of water. For example, to create 1 liter of 5% sugar solution from a 10% solution, you would mix 500ml of the 10% solution with 500ml of water.
What is the percent concentration when 30gms of codeine is dissolved in 2 liters of solution?
The percent concentration of the codeine solution is 1.5%. This is calculated by dividing the mass of codeine (30g) by the total mass of the solution (2000g, since 1 liter of water is approximately 1000g) and then multiplying by 100.
How would you prepare 1 Liter of an alcohol-water solution that is 5 volume percent alcohol?
To prepare 1 liter of a 5% alcohol-water solution, you would mix 50 mL of alcohol with 950 mL of water. This ratio would give you a total volume of 1 liter with 5% of it being alcohol.
What are the way to express concentration of solution?
Concentration of a solution can be expressed in several ways, including molarity (moles of solute per liter of solution), mass percent (mass of solute divided by total mass of solution, multiplied by 100), and molality (moles of solute per kilogram of solvent). Other methods include volume percent (volume of solute divided by total volume of solution, multiplied by 100) and normality (equivalents of solute per liter of solution). Each method is useful depending on the context and the nature of the chemical reaction or process involved.
How many ml are needed to prepare 1 liter of 2.5 percent dextrose solution?
25
A chemist has one solution that is 60 percent chlorinated and another that is 40 percent chlorinated How much of each solution is needed to make a 100 liter solution that is 50 percent chlorinated?
50 Liters of the 60% solution.
If 5 liters of a 4 percent silver iodide solution must be mixed with a 10 percent solution to get a 6 percent solution How many liters of the 10 percent solution are needed?
Let x be the number of liters of the 10% solution needed. The amount of silver iodide in the 5-liter solution is 0.04 * 5 = 0.2 liters. The final amount of silver iodide in the mixture would be 5 * 0.06 = 0.3 liters. Set up the equation: 0.1x + 0.2 = 0.3, solve for x, x = 1 liter. Hence, 1 liter of the 10% solution is needed.
How many ml of 15 percent solution are needed to make 1 gal of 2.5 percent solution?
(X gal)(0.15) = (1 gal)(0.025)0.15X = 0.025X = 0.17 gallons (4 quarts/1 gal.)(1 liter/1.06 quarts)(1000 ml/1 liter)= 642 milliliters============
How much glucose is in one liter of 5 percent dextrose in water?
A 5 percent dextrose solution contains 5 grams of dextrose (glucose) per 100 milliliters of solution. Therefore, in one liter (1000 milliliters) of a 5 percent dextrose solution, there would be 50 grams of glucose.
How would you prepare a liter of 10 percent ammonia solution from the official strong ammonia solution?
To prepare a liter of 10% ammonia solution from the official strong solution: Calculate the volume of the concentrated ammonia solution needed using the dilution formula: C1V1 = C2V2. Measure the calculated volume of the concentrated ammonia solution and add distilled water to make a total volume of 1 liter. Mix thoroughly to ensure uniform distribution.
How much 50 percent dextrose to add to 1 Liter bag to make 5 percent solution?
50 ml
Calculate the volume of solution needed to dissolve 0.25 moles NaCl to make a 3.0M solution?
3.00 M, or 3 moles per (L) "liter" calls for having 3 moles per liter of the solution. The question asks how many moles must be in 250ml of a solution that has 3 moles per Liter. You must ask yourself what percent of 1 Liter is 250mls? Since there are a thousand ml in one liter, (1000ml=1L), then 250ml is exactly 25% of a Liter, or .25L. So, 250ml can only hold 25% of the 3.00 Molarity. Meaning that you multiply 3 x .25 and get .75 moles.
How much sodium bicarbonate is needed to make a 3 percent solution in 1 liter of water?
This is from the website linked to the left of this answer under Web Links:Solubility:7.8g/100g water @ 18 °C (64 °F).Therefore, in 1 liter, 78.0 grams of NaHCO3 will dissolve to make a saturated solution.
How many grams of KCl is needed to make 2 molar solution in 1 liter of water?
To prepare a 2 M solution of KCl in 1 liter of water, you would need to dissolve 149.5 grams of KCl. This is because the molar mass of KCl is approximately 74.5 g/mol, and 2 moles of KCl are needed to prepare a 2 M solution in 1 liter of water.
How much pure alcohol is in 300 liters of 30 percent alcohol solution?
To find the amount of pure alcohol in a 300-liter solution that is 30 percent alcohol, you can multiply the total volume by the percentage of alcohol. This calculation is as follows: 300 liters × 0.30 = 90 liters. Therefore, there are 90 liters of pure alcohol in the 300-liter solution.
How much of a 50 percent solution should be added to 1 liter to make a 25 percent solution?
Mix this 50% solution in equal quantities with water(?) to halve it's strength. So use 1 litre of the 50% solution and 1 litre of water of that's what you are diluting it with.
