Let x be the number of liters of the 10% solution needed. The amount of silver iodide in the 5-liter solution is 0.04 * 5 = 0.2 liters. The final amount of silver iodide in the mixture would be 5 * 0.06 = 0.3 liters. Set up the equation: 0.1x + 0.2 = 0.3, solve for x, x = 1 liter. Hence, 1 liter of the 10% solution is needed.
To convert a 10% sugar solution into a 5% sugar solution, you would need to dilute the original solution by adding a calculated amount of water. For example, to create 1 liter of 5% sugar solution from a 10% solution, you would mix 500ml of the 10% solution with 500ml of water.
The percent concentration of the codeine solution is 1.5%. This is calculated by dividing the mass of codeine (30g) by the total mass of the solution (2000g, since 1 liter of water is approximately 1000g) and then multiplying by 100.
To prepare 1 liter of a 5% alcohol-water solution, you would mix 50 mL of alcohol with 950 mL of water. This ratio would give you a total volume of 1 liter with 5% of it being alcohol.
Scientists express the concentration of a solution primarily in two ways: molarity and mass percent. Molarity is defined as the number of moles of solute per liter of solution, while mass percent represents the mass of solute divided by the total mass of the solution, multiplied by 100. These methods allow for precise communication of how much solute is present in a given volume or mass of solution.
25
50 Liters of the 60% solution.
Let x be the number of liters of the 10% solution needed. The amount of silver iodide in the 5-liter solution is 0.04 * 5 = 0.2 liters. The final amount of silver iodide in the mixture would be 5 * 0.06 = 0.3 liters. Set up the equation: 0.1x + 0.2 = 0.3, solve for x, x = 1 liter. Hence, 1 liter of the 10% solution is needed.
(X gal)(0.15) = (1 gal)(0.025)0.15X = 0.025X = 0.17 gallons (4 quarts/1 gal.)(1 liter/1.06 quarts)(1000 ml/1 liter)= 642 milliliters============
A 5 percent dextrose solution contains 5 grams of dextrose (glucose) per 100 milliliters of solution. Therefore, in one liter (1000 milliliters) of a 5 percent dextrose solution, there would be 50 grams of glucose.
To prepare a liter of 10% ammonia solution from the official strong solution: Calculate the volume of the concentrated ammonia solution needed using the dilution formula: C1V1 = C2V2. Measure the calculated volume of the concentrated ammonia solution and add distilled water to make a total volume of 1 liter. Mix thoroughly to ensure uniform distribution.
50 ml
3.00 M, or 3 moles per (L) "liter" calls for having 3 moles per liter of the solution. The question asks how many moles must be in 250ml of a solution that has 3 moles per Liter. You must ask yourself what percent of 1 Liter is 250mls? Since there are a thousand ml in one liter, (1000ml=1L), then 250ml is exactly 25% of a Liter, or .25L. So, 250ml can only hold 25% of the 3.00 Molarity. Meaning that you multiply 3 x .25 and get .75 moles.
This is from the website linked to the left of this answer under Web Links:Solubility:7.8g/100g water @ 18 °C (64 °F).Therefore, in 1 liter, 78.0 grams of NaHCO3 will dissolve to make a saturated solution.
To prepare a 2 M solution of KCl in 1 liter of water, you would need to dissolve 149.5 grams of KCl. This is because the molar mass of KCl is approximately 74.5 g/mol, and 2 moles of KCl are needed to prepare a 2 M solution in 1 liter of water.
Mix this 50% solution in equal quantities with water(?) to halve it's strength. So use 1 litre of the 50% solution and 1 litre of water of that's what you are diluting it with.
200 ppm solution means 200 mg/liter 200 mg = (100 *0.2)/37 = 0.540 g of 37% formaldehyde Vol of 0.540 g of 37 % formaldehyde= 0.540/1.09 = 0.496 mL of 37 % of formaldehyde Therefore: 0.496 mL/1 liter.