Barium 137 has 56 protons and 56 electrons.
Examples: Ca, Mg, Ba, Sr, Ra, etc.
Ba2+ is the ion of the Ba atom. That means it has given away two electrons to other atoms in order to reach a stable state with 8 electrons in its outer shell.
All should lose 2 electrons to attain the nearest noble gas configuration
To determine if Ba will gain or lose electrons, look at its position on the periodic table. Barium is in Group 2, so it typically loses 2 electrons to form a 2+ cation.
Barium (Ba) has 2 valence electrons in its outer shell. Therefore, it does not have any 5p electrons.
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Barium 137 has 56 protons and 56 electrons.
Barium (Ba) has an atomic number of 56, which means it has 56 electrons in a neutral atom. The "2" you mentioned likely refers to the charge on the barium ion (Ba2+), which means it has lost two electrons, resulting in 54 electrons in the Ba2+ ion.
Barium has two valence electrons, as can be deduced from its placement in Group 2 of the modern periodic table.
Ba2+ ion has a total of 56 electrons. Barium (Ba) has 56 electrons in its neutral state, and when it loses two electrons to become Ba2+, it now has 54 electrons remaining.
Examples: Ca, Mg, Ba, Sr, Ra, etc.
Krypton (Kr) has a total number of 36 electrons, which is the same as the number of core electrons in barium (Ba).
Ba2+ is the ion of the Ba atom. That means it has given away two electrons to other atoms in order to reach a stable state with 8 electrons in its outer shell.
There are 2 valence electrons in Barium.
All should lose 2 electrons to attain the nearest noble gas configuration
To determine if Ba will gain or lose electrons, look at its position on the periodic table. Barium is in Group 2, so it typically loses 2 electrons to form a 2+ cation.