7.95x10^24
To calculate the number of atoms in 13.2 mol of copper, you can use Avogadro's number, which is approximately 6.022 x 10^23 atoms per mole. Multiply 13.2 mol by Avogadro's number to get the number of atoms: 13.2 mol * (6.022 x 10^23 atoms/mol) = 7.93 x 10^24 atoms. Therefore, there are approximately 7.93 x 10^24 atoms in 13.2 mol of copper.
Silver has a greater atomic mass than copper. The atomic mass of silver is approximately 107.87 g/mol, while the atomic mass of copper is approximately 63.55 g/mol.
To find the number of phosphorus atoms in 8.90 mol of copper(II) phosphate (Cu₃(PO₄)₂), we first identify that each formula unit contains 2 phosphorus (P) atoms. Thus, in 8.90 mol of copper(II) phosphate, the total number of phosphorus atoms is calculated as follows: 8.90 mol × 2 P/mol = 17.8 mol of phosphorus atoms. To convert moles to atoms, we multiply by Avogadro's number (approximately (6.022 \times 10^{23}) atoms/mol): 17.8 mol × (6.022 \times 10^{23}) atoms/mol ≈ (1.07 \times 10^{24}) phosphorus atoms.
The molar mass of copper chloride is 98.999 g/mol.
Cu2(C2H3O2)4 + 2Na2S --> 2CuS + 4Na(C2H3O2) 170 mL Cu2(C2H3O2)4 X 1 L/ 1OOO mL X .3 M/ 1 Mol X 2 Mol CuS/ 1 Mol Cu2(C2H3O2)4 X 159.157 g/ 1 Mol CuS = 16.2 g
Also 5,8 mol
If zinc reacts with excess copper(ll) sulfate, a 1:1 molar ratio will be maintained. Therefore, 5.8 mol of zinc will produce 5.8 mol of copper.
There are 1 mol of phosphorus atoms in 1 mol of copper (II) phosphate. Therefore, in 3.30 mol of copper (II) phosphate, there are 3.30 mol of phosphorus atoms, which is equivalent to 3.30 x 6.022 x 10^23 = 1.97 x 10^24 atoms of phosphorus.
To find the weight of 0.252 mol of copper, you need to multiply the number of moles by the molar mass of copper. The molar mass of copper is approximately 63.55 g/mol. Therefore, 0.252 mol of copper would weigh approximately 15.99 grams.
To determine the number of atoms in 6.4g of copper, you first need to find the number of moles using the molar mass of copper (63.55 g/mol). Then, you can use Avogadro's number (6.022 x 10^23 atoms/mol) to calculate the number of atoms. The final calculation would be: (6.4g / 63.55g/mol) * 6.022 x 10^23 atoms/mol.
6.022*10**23 atoms / mol = avagadro's constant 63.546 g / mol = atomic weight of copper 1 atom / 6.022*10**23 atoms/mol * 63.546 g/mol = 1.05523082*10**-22g 1 g / 63.546 g/mol * 6.022*10**23 atoms/mol = 9.476599629*10**21 atoms
To calculate the mass of 4.75 mol of copper (II) nitrate, you need to first find the molar mass of Cu(NO3)2 which is 187.55 g/mol. Then, multiply the molar mass by the number of moles (4.75 mol) to get the mass: 187.55 g/mol * 4.75 mol = 890.56 grams. So, the mass of 4.75 mol of copper (II) nitrate is 890.56 grams.
The molar mass of copper (Cu) is approximately 63.55 g/mol. To calculate the weight of 2.18 mol of copper, you would multiply the number of moles by the molar mass: 2.18 mol x 63.55 g/mol ≈ 138.49 g. Therefore, 2.18 mol of copper weighs approximately 138.49 grams.
There are 1 atom of phosphorus in each formula unit of copper(II) phosphate, which is Cu3(PO4)2. Therefore, in 4.40 mol of copper(II) phosphate, there are 4.40 mol of phosphorus atoms, which is 4.40 x 6.022 x 10^23 atoms.
1 mol Cu Atoms (6.02x10^23 atoms)
b. 7.95 ´ 1024 atoms
To find the number of atoms in 1.2 grams of copper, you need to first determine the molar mass of copper (Cu). The molar mass of copper is 63.55 g/mol. Next, calculate the number of moles in 1.2 grams of copper (1.2 g / 63.55 g/mol = 0.0189 mol). Finally, use Avogadro's number (6.022 x 10^23 atoms/mol) to convert moles to atoms: 0.0189 mol x 6.022 x 10^23 atoms/mol = approximately 1.14 x 10^22 atoms.