There are five different d orbitals within the 3d sublevel: 3dz², 3dxz, 3dyz, 3dx²-y², and 3dxy.
If m sub l is three, then there can be 7 orbitals, since the l value (the one that corresponds to the orbitals) would be 3 (denoting the f orbital).
That would be 1s2, 2s2, 2p6 are the 3 orbitals that are completely filled. The other one is not filled because it only has 1 configuration. Hopefully this help....if not I apologize. *PUMA #4*
This may be trick question.In practise to make up the octet which would give sodium the electronic configutration of Argon, there is ony space for 7.However the electronic confugration of sodium is [Ne]3s1The outer shell, 3, has the following orbitals.3s, three p orbtals 3px, 3py, 3pz AND five d orbitals , and 3dx2, 3dxy, 3dyz, 3dzx, 3dx2-y2 (sorry the sufixes don't come out right- you need to look at a text book)Theoretically then we have space for 18 electrons in the outershell, so sodium could take on 17!
The range of the levels is between 0 to n-1. 3 minus 1 equals to 2, so we have 0, 1, 2 as sub levels. They are the same number of sub-levels.
i think it's meant to be NO4 3- .. an ion because it's NO2 - and NO3 2- but then i don't know how they're actually bonded! i guess there's deffo one dative bond between N and O and then either 3 dot cross ones ..or another dative from n to o and one from an o to n and one dot cross! but i expect it's three dot crosses and one dative! because it's more even.. probs. guut luck anyway :D i think it's meant to be NO4 3- .. an ion because it's NO2 - and NO3 2- but then i don't know how they're actually bonded! i guess there's deffo one dative bond between N and O and then either 3 dot cross ones ..or another dative from n to o and one from an o to n and one dot cross! but i expect it's three dot crosses and one dative! because it's more even.. probs. guut luck anyway :D