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This may be trick question.

In practise to make up the octet which would give sodium the electronic configutration of Argon, there is ony space for 7.

However the electronic confugration of sodium is [Ne]3s1

The outer shell, 3, has the following orbitals.

3s, three p orbtals 3px, 3py, 3pz AND five d orbitals , and 3dx2, 3dxy, 3dyz, 3dzx, 3dx2-y2 (sorry the sufixes don't come out right- you need to look at a text book)

Theoretically then we have space for 18 electrons in the outershell, so sodium could take on 17!

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Q: How many empty spaces are there for electrons on the outer ring of sodium?
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