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How many Chlorine electrons are in the outer shell of a sodium atom?
None - the electron goes from sodium TO the chlorine.
How many electron are transfer in the ionic bond between sodium amd chlorine in naCI?
In the ionic bond between sodium and chlorine in NaCl, one electron is transferred from the sodium atom to the chlorine atom. Sodium loses one electron to achieve a stable electron configuration with a full outer shell, while chlorine gains the electron to also achieve a full outer shell.
How many electrons are in the outer shell of chlorine?
7
How many electrons are in valence shell of a sodium atom before and after reaction with chlorine gas to give sodium chloride NaCl?
A sodium atom has 1 electron in its valence shell, while a chlorine atom has 7 electrons in its valence shell. When sodium reacts with chlorine to form sodium chloride, the sodium atom loses its 1 electron to achieve a stable octet configuration, while the chlorine atom gains this electron. The resulting sodium chloride molecule has 8 electrons in the valence shell of the chlorine atom.
What happens when a chlorine atom gains an electron in it's outer energy shell?
When a chlorine atom gains an electron in its outer energy shell, it becomes a negatively charged ion called a chloride ion. This extra electron fills its outer shell, giving it a stable electron configuration similar to that of a noble gas. Chloride ions commonly combine with sodium ions to form salt, sodium chloride.
How many Chlorine electrons are in the outer shell of a sodium atom?
None - the electron goes from sodium TO the chlorine.
Why does the transfer of an electron occur between a sodium atom and a chlorine atom?
The transfer of an electron between a sodium atom and a chlorine atom occurs because sodium has one electron in its outer shell that it wants to lose to achieve a more stable electron configuration, while chlorine has seven electrons in its outer shell and can gain one from sodium to complete its outer shell and achieve stability by forming a full octet. This transfer of electrons results in the formation of sodium chloride, an ionic compound.
How many electron are transfer in the ionic bond between sodium amd chlorine in naCI?
In the ionic bond between sodium and chlorine in NaCl, one electron is transferred from the sodium atom to the chlorine atom. Sodium loses one electron to achieve a stable electron configuration with a full outer shell, while chlorine gains the electron to also achieve a full outer shell.
Why does 1 sodium atom bond with 1 chlorine atom?
Sodium has one electron in its outer shell, which it wants to lose to achieve a stable electron configuration. Chlorine, on the other hand, needs one electron to complete its outer shell. By transferring an electron from the sodium atom to the chlorine atom, both atoms achieve a full outer shell, forming a stable ionic bond.
How many electrons are in the outer shell of chlorine?
7
How many electrons are in valence shell of a sodium atom before and after reaction with chlorine gas to give sodium chloride NaCl?
A sodium atom has 1 electron in its valence shell, while a chlorine atom has 7 electrons in its valence shell. When sodium reacts with chlorine to form sodium chloride, the sodium atom loses its 1 electron to achieve a stable octet configuration, while the chlorine atom gains this electron. The resulting sodium chloride molecule has 8 electrons in the valence shell of the chlorine atom.
What happens when a chlorine atom gains an electron in it's outer energy shell?
When a chlorine atom gains an electron in its outer energy shell, it becomes a negatively charged ion called a chloride ion. This extra electron fills its outer shell, giving it a stable electron configuration similar to that of a noble gas. Chloride ions commonly combine with sodium ions to form salt, sodium chloride.
When a sodium atom reacts with a chlorine atom to form a compound the electron configurations of the ions forming the compound are the same as those of noble gas atoms?
That is correct. A noble gas (or at least all the noble gas elements heavier than helium) has an electron configuration of 8 electrons in its outer shell, and the sodium and chlorine ions in sodium chloride also have 8 electrons in their outer shell, just like a noble gas atom.
What number of electrons in the outer outer shell of Cl?
A chloride anion contains eight outer shell electrons, one more than the seven outer shell electrons found in a chlorine atom.
Why is it easier to remove an electron from sodium atom than a chlorine atom?
It is easier to remove an electron from a sodium atom than from a chlorine atom because sodium has a single valence electron in its outer shell, which is more loosely held and experiences less effective nuclear charge. In contrast, chlorine has seven valence electrons and a higher effective nuclear charge, meaning its outer electrons are held more tightly. Consequently, removing an electron from sodium requires less energy compared to chlorine.
What will an atom of chlorine do to complete its outer shell?
An atom of chlorine has seven electrons in its outer shell and requires one additional electron to complete its octet. To achieve this stable configuration, a chlorine atom will typically gain or share an electron through chemical bonding, often forming an anion (Cl⁻) when it gains an electron from another atom. This process allows chlorine to attain a full outer shell, enhancing its stability.
What happens to the electron in a chlorine atom and a sodium atom when they combine?
When a chlorine atom and a sodium atom combine to form sodium chloride (table salt), the sodium atom loses its outer electron to the chlorine atom. The electron is transferred from sodium to chlorine, resulting in a sodium cation (Na+) and a chloride anion (Cl-), which then form an ionic bond due to the electrostatic attraction between the oppositely charged ions.
