To convert grams to Atomic Mass units (amu), we use the conversion factor that 1 atomic mass unit is approximately (1.66 \times 10^{-24}) grams. Therefore, to find the number of atomic mass units in 5.7 grams, we can use the formula:
[ \text{Number of amu} = \frac{5.7 , \text{g}}{1.66 \times 10^{-24} , \text{g/amu}} \approx 3.43 \times 10^{24} , \text{amu}. ]
Thus, 5.7 grams is approximately (3.43 \times 10^{24}) atomic mass units.
If an atom has an atomic mass of 101g and 57 neutrons, then:Atomic Mass = (number of protions) + (number of neutrons) 101 = (X) + (57) or.... (101) - (57) = x 101-57=44 the element that has 44 as its atomic number would be RutheniumAs we know mass of atom is primaril constituted by the neutrons and protons,while the mass of electron is neglegible.Taking mass of proton equal to mass of neutron and both having a unit mass.we can say that mass of an atom is equal to the number of protons and neutrons multiplied with the mass of i proton/neutron.we are given mass of lithium =7=>(no. of neutron + no. of protons)*(mass of 1 proton/neutron)=7=>no. of neutrons + no. of protons *(1)=7=>no. of neutrons=7-no. of protons=>no. of neutrons=7-3 (atomic no=no. of protons)=>no. of neutrons=4
Lanthanum's atomic number is 57 thus it has 57 protons, the number of protons an atom has is equal to the atomic weight, in this case 141 minus the number of protons or 57 so, 141-57=84 Lanthanum-141 has 84 neutrons.
The approximate atomic weight (not molar mass) of aluminium is 26,98 amu.The value after IUPAC Table of atomic weights is 26,981 538 57(1).
57 grams Florine (1 mole F/19.00 grams)(6.022 X 10^23/1 mole F) = 1.8066 X 10^24 atoms Florine 1.8066 X 10^24 atoms (1 mole Co/6.022 X 10^23)(58.93 grams/1 mole Co) = 176.79 grams of cobalt ( sigi figi might be 180 grams )
Molybdenum-96 (not Mo-96) or Mo 96 42 has 42 protons and 54 neutrons. The atomic number is number of protons The mass number minus the atomic number is number of neutrons
If an atom has an atomic mass of 101g and 57 neutrons, then:Atomic Mass = (number of protions) + (number of neutrons) 101 = (X) + (57) or.... (101) - (57) = x 101-57=44 the element that has 44 as its atomic number would be RutheniumAs we know mass of atom is primaril constituted by the neutrons and protons,while the mass of electron is neglegible.Taking mass of proton equal to mass of neutron and both having a unit mass.we can say that mass of an atom is equal to the number of protons and neutrons multiplied with the mass of i proton/neutron.we are given mass of lithium =7=>(no. of neutron + no. of protons)*(mass of 1 proton/neutron)=7=>no. of neutrons + no. of protons *(1)=7=>no. of neutrons=7-no. of protons=>no. of neutrons=7-3 (atomic no=no. of protons)=>no. of neutrons=4
Lanthanum's atomic number is 57 thus it has 57 protons, the number of protons an atom has is equal to the atomic weight, in this case 141 minus the number of protons or 57 so, 141-57=84 Lanthanum-141 has 84 neutrons.
Lanthanum has 57 protons and 81-82 neutrons.
To find the number of moles in 57 grams of Xenon, divide the given mass (in grams) by the molar mass of Xenon. The molar mass of Xenon is 131.3 grams/mol. Therefore, 57 grams of Xenon is equal to 0.434 moles (57/131.3).
The atomic number of ruthenium (Ru) is 44.The atomic weight of Ru is 101.07 grams per mole.See the Web Links to the left of this answer for a periodic table with more information about this element!
The approximate atomic weight (not molar mass) of aluminium is 26,98 amu.The value after IUPAC Table of atomic weights is 26,981 538 57(1).
To calculate the atomic weight of exonium, you would multiply the mass of each isotope by its abundance, add these values together, and then divide by 100. For exonium: Atomic weight = (57% * 96 amu) + (43% * 117 amu) / 100 = (54.72) + (50.31) / 100 = 105.03 amu
57 grams Florine (1 mole F/19.00 grams)(6.022 X 10^23/1 mole F) = 1.8066 X 10^24 atoms Florine 1.8066 X 10^24 atoms (1 mole Co/6.022 X 10^23)(58.93 grams/1 mole Co) = 176.79 grams of cobalt ( sigi figi might be 180 grams )
Ruthenium has 44 protons since the atomic number represents the number of protons in an atom. Since the mass number is 101, it implies the sum of protons and neutrons in the nucleus is 101, so the number of neutrons in this case would be 101 - 44 = 57.
I am understanding you to mean an iron-57 ion with a charge of 3+.The atomic number of Fe is 26, which means that all Fe atoms or ions have 26 protons in their nuclei.In a neutral Fe atom, the number of electrons would be the same as the number of protons, which is 26. The charge on the Fe ion is 3+, which means the Fe atom has given up 3 electrons. So the number of electrons in an Fe3+ ion is 26-3, which is 23.The mass number of iron-57 = 57. The mass number is the sum of protons and neutrons in the atomic nuclei of iron-57 atoms. We know the number of protons is 26. The number of neutrons = mass number - the number of protons, which is 57-26 = 31 neutrons.To summarize:The number of protons in all Fe atoms is 26.The number of electrons in an any Fe3+ ion is 23.The number of neutrons in an iron-57 atom is 31.
To find the units digit of (29^{57}), we can focus on the units digit of the base, which is 9. The units digits of powers of 9 follow a pattern: (9^1 = 9), (9^2 = 81) (units digit 1), (9^3 = 729) (units digit 9), and (9^4 = 6561) (units digit 1). This pattern alternates between 9 and 1. Since (57) is odd, the units digit of (29^{57}) is the same as that of (9^{57}), which is (9). Thus, the units digit of (29^{57}) is (9).
By unit of length and mass and conversion ,we can say that 1 in =2.545 cm 57 in=144.78 cm