1 mol of anything = 6.022x1023 atoms
so 1.4 mole = 1.4 * 6.022x1023 atoms / mole = 8.4308x1023 atoms
Your compound's chemical formula is (NH4)2Cr2O7 - so you can see that it contains 2 moles of NH4+ per mole of the salt. So in 7 moles you have 14 moles of ammonium, containing 14 moles of N atoms which means that you have (1 mole = 6,022*10^23 atoms) 14 mols * 6,022*10^23 atoms/mole = 8,43*10^23 atoms
Since the normal formula for elemental nitrogen is N2, this answer is twice the atomic mass of nitrogen or 28 grams. The mass of a mole of nitrogen atoms is half this.
To find the number of moles of nickel atoms in (8.00 \times 10^9) Ni atoms, you can use Avogadro's number, which is approximately (6.022 \times 10^{23}) atoms/mole. The calculation is as follows: [ \text{Moles of Ni} = \frac{8.00 \times 10^9 \text{ atoms}}{6.022 \times 10^{23} \text{ atoms/mole}} \approx 1.33 \times 10^{-14} \text{ moles} ] Thus, there are approximately (1.33 \times 10^{-14}) moles of nickel atoms in (8.00 \times 10^9) Ni atoms.
The atomic mass of ekasilicon is 293.21 grams per mole. It contains 14 silicon atoms and 2 germanium atoms in its molecular structure.
14
Your compound's chemical formula is (NH4)2Cr2O7 - so you can see that it contains 2 moles of NH4+ per mole of the salt. So in 7 moles you have 14 moles of ammonium, containing 14 moles of N atoms which means that you have (1 mole = 6,022*10^23 atoms) 14 mols * 6,022*10^23 atoms/mole = 8,43*10^23 atoms
A mole of any substance contains 6.02x1023 atoms. The surface of the earth is about 510x106 km2. This surface area is the same as 5.10x1014 m2. Therefore each square meter would have (6.02x1023 atoms)/(5.10x1014 m2) atoms/m2. This reduces to 1.18x109 atoms/m2
Since the normal formula for elemental nitrogen is N2, this answer is twice the atomic mass of nitrogen or 28 grams. The mass of a mole of nitrogen atoms is half this.
To find the number of atoms in 14 moles of cadmium, you can use Avogadro's number, which is approximately 6.022 x 10^23 atoms per mole. Therefore, there are approximately 14 x 6.022 x 10^23 atoms in 14 moles of cadmium.
To find the number of moles of nickel atoms in (8.00 \times 10^9) Ni atoms, you can use Avogadro's number, which is approximately (6.022 \times 10^{23}) atoms/mole. The calculation is as follows: [ \text{Moles of Ni} = \frac{8.00 \times 10^9 \text{ atoms}}{6.022 \times 10^{23} \text{ atoms/mole}} \approx 1.33 \times 10^{-14} \text{ moles} ] Thus, there are approximately (1.33 \times 10^{-14}) moles of nickel atoms in (8.00 \times 10^9) Ni atoms.
1 mole of carbon-14 atoms. (probably what your instructor is looking for) More specifically, One mole of the isobar (elements with the same number of nucleons) with 14 nucleons: Be-14, B-14, C-14, N-14, O-14, F-14 are all suitable elements of which 1 mole of any of them (or a combination of all of them) will equal 14 grams. Also, any 1 mole of a molecule with a molecular weight of 14 will weigh 14 grams. An example: Methane: CH4 IFF the carbon atom is a C-10 and the hydrogens are H-1. Or half a mole of Silicon-28, and so on... Mess with your professor a bit. It's good for them. haha!
Let us find Magnesium atoms first. 15 grams magnesium (1 mole Mg/24.31 grams)(6.022 X 10^23/1 mole Mg) = 3.72 X 10^23 atoms magnesium Now take this an drive to grams sodium 3.72 X 10^23 atoms (1 mole Na/6.022 X 10^23)(22.99 grams/1 mole Na) = 14 grams of sodium ----------------------------
To find the mass of the nitrogen atoms in one mole of cadmium nitrate, calculate the molar mass of cadmium nitrate (Cd(NO3)2) and then multiply it by the number of nitrogen atoms in one mole of cadmium nitrate (2 nitrogen atoms). The molar mass of cadmium nitrate is 236.41 g/mol. Therefore, the mass of the nitrogen atoms in one mole of cadmium nitrate is 28.02 g.
14
The atomic mass of ekasilicon is 293.21 grams per mole. It contains 14 silicon atoms and 2 germanium atoms in its molecular structure.
For every one mole of C6H14O6 there are 14 of hydrogen (H). 1 mole is equal to Avogadro's number of 6.0221413e+23. Therefore to calculate total atoms of H you multiply 14 by Avogadro's number.
Since 14 (4+10) moles of P4O10 contains 4 moles of Phosphorus, 8 moles of P4O10 will contain :: (8 x 4)/14 = 2.286 moles of Phosphorus