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1 mol of anything = 6.022x1023 atoms

so 1.4 mole = 1.4 * 6.022x1023 atoms / mole = 8.4308x1023 atoms

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How many nitrogen atoms would be present in 7 moles of NH42C2O4?

Your compound's chemical formula is (NH4)2Cr2O7 - so you can see that it contains 2 moles of NH4+ per mole of the salt. So in 7 moles you have 14 moles of ammonium, containing 14 moles of N atoms which means that you have (1 mole = 6,022*10^23 atoms) 14 mols * 6,022*10^23 atoms/mole = 8,43*10^23 atoms


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What has a mass of 14 g?

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To find the mass of the nitrogen atoms in one mole of cadmium nitrate, calculate the molar mass of cadmium nitrate (Cd(NO3)2) and then multiply it by the number of nitrogen atoms in one mole of cadmium nitrate (2 nitrogen atoms). The molar mass of cadmium nitrate is 236.41 g/mol. Therefore, the mass of the nitrogen atoms in one mole of cadmium nitrate is 28.02 g.


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