Your compound's chemical formula is (NH4)2Cr2O7 - so you can see that it contains 2 moles of NH4+ per mole of the salt. So in 7 moles you have 14 moles of ammonium, containing 14 moles of N atoms which means that you have
(1 mole = 6,022*10^23 atoms)
14 mols * 6,022*10^23 atoms/mole = 8,43*10^23 atoms
To find the number of moles of nitrogen in (1.61 \times 10^{24}) atoms, you can use Avogadro's number, which is approximately (6.022 \times 10^{23}) atoms per mole. Calculating the moles: [ \text{Moles of nitrogen} = \frac{1.61 \times 10^{24} \text{ atoms}}{6.022 \times 10^{23} \text{ atoms/mole}} \approx 2.68 \text{ moles} ] Thus, there are approximately 2.68 moles of nitrogen in (1.61 \times 10^{24}) atoms.
Three moles of N2O4 contains six moles of nitrogen atoms (N) and twelve moles of oxygen atoms (O), since each molecule of N2O4 consists of two nitrogen atoms and four oxygen atoms. Therefore, in total, there are 18 atoms in three moles of N2O4.
To find the number of nitrogen atoms in 5.00 g of magnesium nitride (Mg₃N₂), first calculate the molar mass of Mg₃N₂, which is approximately 100.95 g/mol (24.31 g/mol for Mg and 14.01 g/mol for N). The number of moles in 5.00 g of Mg₃N₂ is about 0.0495 moles. Since each formula unit of Mg₃N₂ contains 2 nitrogen atoms, the total number of nitrogen atoms is calculated as: 0.0495 moles × 2 × 6.022 × 10²³ atoms/mole, which equals approximately 5.95 × 10²² nitrogen atoms.
The answer is 24,92 g nitrogen.
There is one atom in nitrogen there is not one atom of nitrogen, there is one molecule of nitrogen. There is 6.02 * 10^23 atoms in 1 mole of nitrogen. Or simply the natural state of nitrogen is n2. or two nitrogen atoms to a molecule. =]
Since each N2O molecule contains 2 nitrogen atoms, the number of moles of N2O molecules would be half of the moles of nitrogen atoms. Therefore, in this case, there would be 2.615 moles of N2O molecules present in the sample.
1.38 moles of nitrogen equal16,62110876532.1023 atoms; the molecule of nitrogen is diatomic.
Since quinine has a nitrogen atom in its chemical formula, 1 mole of quinine contains 1 mole of nitrogen atoms. Therefore, in 2.5 x 10^-2 moles of quinine, there are also 2.5 x 10^-2 moles of nitrogen atoms.
3 x 12 = 36 moles of Nitrogen atoms N or 18 moles of Nitrogen molecules N2
1.38 moles of nitrogen equal16,62110876532.1023 atoms; the molecule of nitrogen is diatomic.
To find the number of moles of nitrogen in (1.61 \times 10^{24}) atoms, you can use Avogadro's number, which is approximately (6.022 \times 10^{23}) atoms per mole. Calculating the moles: [ \text{Moles of nitrogen} = \frac{1.61 \times 10^{24} \text{ atoms}}{6.022 \times 10^{23} \text{ atoms/mole}} \approx 2.68 \text{ moles} ] Thus, there are approximately 2.68 moles of nitrogen in (1.61 \times 10^{24}) atoms.
Three moles of N2O4 contains six moles of nitrogen atoms (N) and twelve moles of oxygen atoms (O), since each molecule of N2O4 consists of two nitrogen atoms and four oxygen atoms. Therefore, in total, there are 18 atoms in three moles of N2O4.
yes it contains two moles of nitrogen because NH4NO3 has two nitrogen therefore it equals to 2 moles on nitrogen.
At standard temperature and pressure, nitrogen exists as diatomic molecules. Therefore the number of atoms in 3.4 moles is 2 X 3.4 X Avogadro's Number, or 4.1 X 1024 atoms, to the justified number of significant digits.
five
There are 3 moles of nitrogen in 3 moles of ammonium nitrate. Ammonium nitrate contains 2 nitrogen atoms in its chemical formula NH4NO3. Each mole of ammonium nitrate contains 2 moles of nitrogen atoms.
Molar mass of Fe(NO3)2 is 55.85 + 2(14.00 + 3(16.00)) = 179.85 g/mol Therefore, number of moles of Fe(NO3)2 present is 53.55/179.85 = 0.2977 mol For each molecule of Fe(NO3)2, there are two atoms of nitrogen associated with it. Therefore, there are 0.2977*2 = 0.5954 mol of nitrogen atoms