0
Since the atomic weight of oxygen is 15.9994 or 15.9994 grams/mole 16.00 grams of O would be 1.000 moles. 1 mole of something contains Avogadro's number (6.0221415 × 1023 mol-1) of particles of that substance - in this case atoms so 16.00 grams of O would be 6.0221415 × 1023 atoms of O.
What else can I help you with?
How many atoms are present in 16g of o and 8g pf sulphur?
To find the number of atoms in 16 g of oxygen (O), we first determine the number of moles: 16 g of O divided by its molar mass (approximately 16 g/mol) gives 1 mole of O, which contains about 6.022 x 10²³ atoms. For 8 g of sulfur (S), the molar mass is approximately 32 g/mol, so 8 g corresponds to 0.25 moles, equating to about 1.505 x 10²³ atoms of S. In total, there are approximately 7.527 x 10²³ atoms from both elements combined.
How many moles of oxygen atoms are in 2.53 g of calcium hydroxide?
The answer is 0,068 mol (for O not for O2).
How many atoms in 16g of O and 8g of S?
In 16g of O, there are approximately 3.02 x 10^23 atoms, as the atomic mass of oxygen is 16 g/mol. In 8g of S, there are approximately 6.02 x 10^23 atoms, as the atomic mass of sulfur is 32 g/mol.
How many atoms are present in 16 g of o and 8 g of s?
To find the number of atoms in 16 g of oxygen (O) and 8 g of sulfur (S), we first calculate the moles of each element. The molar mass of oxygen is approximately 16 g/mol, so 16 g of O contains 1 mole, which equals (6.022 \times 10^{23}) atoms. The molar mass of sulfur is about 32 g/mol, so 8 g of S contains 0.25 moles, which equals (1.5055 \times 10^{23}) atoms. In total, there are approximately (7.527 \times 10^{23}) atoms (1 mole of O + 0.25 moles of S).
How many moles of atoms are in 4.1 x 10-12g O?
To find the number of moles of atoms in 4.1 x 10^(-12) g of oxygen, you first convert the mass to moles by dividing by the molar mass of oxygen (16 g/mol). 4.1 x 10^(-12) g / 16 g/mol = 2.56 x 10^(-13) moles of oxygen atoms.
How many atoms are present in 16g of o and 8g pf sulphur?
To find the number of atoms in 16 g of oxygen (O), we first determine the number of moles: 16 g of O divided by its molar mass (approximately 16 g/mol) gives 1 mole of O, which contains about 6.022 x 10²³ atoms. For 8 g of sulfur (S), the molar mass is approximately 32 g/mol, so 8 g corresponds to 0.25 moles, equating to about 1.505 x 10²³ atoms of S. In total, there are approximately 7.527 x 10²³ atoms from both elements combined.
How many moles of oxygen atoms are in 2.53 g of calcium hydroxide?
The answer is 0,068 mol (for O not for O2).
How many atoms in 16g of O and 8g of S?
In 16g of O, there are approximately 3.02 x 10^23 atoms, as the atomic mass of oxygen is 16 g/mol. In 8g of S, there are approximately 6.02 x 10^23 atoms, as the atomic mass of sulfur is 32 g/mol.
How many atoms are present in 16 g of o and 8 g of s?
To find the number of atoms in 16 g of oxygen (O) and 8 g of sulfur (S), we first calculate the moles of each element. The molar mass of oxygen is approximately 16 g/mol, so 16 g of O contains 1 mole, which equals (6.022 \times 10^{23}) atoms. The molar mass of sulfur is about 32 g/mol, so 8 g of S contains 0.25 moles, which equals (1.5055 \times 10^{23}) atoms. In total, there are approximately (7.527 \times 10^{23}) atoms (1 mole of O + 0.25 moles of S).
How many moles of atoms are in 4.1 x 10-12g O?
To find the number of moles of atoms in 4.1 x 10^(-12) g of oxygen, you first convert the mass to moles by dividing by the molar mass of oxygen (16 g/mol). 4.1 x 10^(-12) g / 16 g/mol = 2.56 x 10^(-13) moles of oxygen atoms.
How many atoms are in 0.700g of P2O5?
To find the number of atoms in 0.700 g of P₂O₅, first calculate the molar mass of P₂O₅, which is approximately 142.0 g/mol (with phosphorus at about 31.0 g/mol and oxygen at about 16.0 g/mol). Next, determine the number of moles in 0.700 g by dividing by the molar mass: 0.700 g / 142.0 g/mol ≈ 0.00493 moles. Since each formula unit of P₂O₅ contains 7 atoms (2 phosphorus and 5 oxygen), multiply the moles by Avogadro's number (approximately (6.022 \times 10^{23}) atoms/mol) to find that there are roughly (1.48 \times 10^{21}) atoms in 0.700 g of P₂O₅.
How many kilogram in 1600 g?
1.6 kg. Why did you ask?
How many total atoms are in 0.400 g of P2O5?
To find the total number of atoms in 0.400 g of P₂O₅, first calculate the molar mass of P₂O₅, which is approximately 283.88 g/mol (with phosphorus (P) at about 30.97 g/mol and oxygen (O) at about 16.00 g/mol). Then, determine the number of moles in 0.400 g by dividing the mass by the molar mass: (0.400 , \text{g} \div 283.88 , \text{g/mol} \approx 0.00141 , \text{mol}). Since each molecule of P₂O₅ contains 7 atoms (2 phosphorus + 5 oxygen), multiply the moles by Avogadro's number (approximately (6.022 \times 10^{23}) atoms/mol) and then by 7, resulting in approximately (5.89 \times 10^{21}) total atoms.
How many total atoms are in 0.330 g of P2O5?
To find the total number of atoms in 0.330 g of P₂O₅, first calculate the molar mass of P₂O₅, which is approximately 283.88 g/mol (with phosphorus at about 30.97 g/mol and oxygen at about 16.00 g/mol). Then, determine the number of moles in 0.330 g: ( \text{moles} = \frac{0.330 , \text{g}}{283.88 , \text{g/mol}} \approx 0.00116 , \text{mol} ). Since each formula unit of P₂O₅ contains 7 atoms (2 phosphorus and 5 oxygen), the total number of atoms is ( 0.00116 , \text{mol} \times 7 , \text{atoms/formula unit} \times 6.022 \times 10^{23} , \text{atoms/mol} \approx 4.87 \times 10^{21} , \text{atoms} ).
How many moles of O atoms are present in a 254g sample of carbon dioxide?
To find the number of moles of oxygen atoms in a 254 g sample of carbon dioxide (CO₂), first calculate the molar mass of CO₂, which is approximately 44 g/mol (12 g/mol for carbon and 32 g/mol for two oxygen atoms). The number of moles of CO₂ in the sample is 254 g ÷ 44 g/mol = about 5.77 moles. Since each molecule of CO₂ contains two oxygen atoms, the total number of moles of oxygen atoms is 5.77 moles × 2 = approximately 11.54 moles of O atoms.
How many atoms are in 49.1740 g of zirconium?
49.1740 g (6.02 x 1023 atoms) / (91.22 g) = 3.25 x 1023 atoms
How many oxygen atoms are present in a 14.0 g sample of Cu(NO3)2?
14.0 g x 1 mole/187.56 g = 0.0746 moles0.0746 moles Cu(NO3)2 x 6 moles O/mole Cu(NO3)2 = 0.448 moles O atoms0.448 moles O atoms x 6.02x10^23 atoms/mole = 2.70x10^23 atoms of oxygen
