The number of molecules is 13,8509239711.10e23.
Approx 7.925*10^23 atoms.
The answer is 7,829.10 ex.23 atoms.
0.125 moles x 6.02x10^23 atoms/mole = 7.53x10^22 atoms
There are 9.33 moles of carbon in 5.62 atoms of carbon.
Divide that number of atoms by 6.02x10^23 atoms/mole
1.50 x 10 to the 23 atoms of fluorine is equal to 0,249 moles.
To find the number of atoms in 0.35 moles of plutonium, you can use Avogadro's number, which is 6.022 x 10^23 atoms/mol. Multiply 0.35 moles by Avogadro's number to get the number of atoms. Therefore, 0.35 moles of plutonium contains approximately 2.1 x 10^23 atoms.
The answer is 7,829.10 ex.23 atoms.
Approx 7.925*10^23 atoms.
0.125 moles x 6.02x10^23 atoms/mole = 7.53x10^22 atoms
There are 9.33 moles of carbon in 5.62 atoms of carbon.
Divide that number of atoms by 6.02x10^23 atoms/mole
3,00 moles of Li have 18,066422571.10e23 atoms.
2.01x10^22 atoms x 1 mole/6.02x10^23 atoms = 0.0334 moles
85 moles Li x 6.02x10^23 atoms/mole Li = 5.17x10^25 atoms of Li
0.3 moles K (6.022 X 10^23/1mol K) = 1.8 X 10^23 atoms of K
Divide that number by Avogadro's number: 3.968x10(23) / 6.02x10(23) = 0.659mol Mg, which would be about 16g.