To find the number of atoms in 27.0 moles of Mercury (Hg), you can use Avogadro's number, which is approximately (6.022 \times 10^{23}) atoms per mole. Therefore, the total number of atoms in 27.0 moles of Hg is calculated as follows:
[ 27.0 , \text{moles} \times 6.022 \times 10^{23} , \text{atoms/mole} \approx 1.63 \times 10^{25} , \text{atoms}. ]
So, there are approximately (1.63 \times 10^{25}) atoms in 27.0 moles of mercury.
55.8 grams
One part of one mole of anything (eg. atoms in a mole atoms) is 1 / (6*10+23) = 1.6*10-24
To convert Torr to mm Hg, divide by 1.33. So, the partial pressure of helium in mm Hg is 439 Torr / 1.33 = 330 mm Hg. To find the partial pressure of hydrogen, subtract the partial pressure of helium from the total pressure: 600 mm Hg - 330 mm Hg = 270 mm Hg. Hence, the partial pressure of hydrogen gas is 270 mm Hg.
To find the number of atoms in 22.9 moles of mercury (Hg), you can use Avogadro's number, which is approximately (6.022 \times 10^{23}) atoms per mole. Multiply the number of moles by Avogadro's number: [ 22.9 , \text{mol} \times 6.022 \times 10^{23} , \text{atoms/mol} \approx 1.38 \times 10^{25} , \text{atoms}. ] Therefore, there are approximately (1.38 \times 10^{25}) atoms in 22.9 moles of Hg.
No Hg, or mercury is an element, but it is not molecular.
There are 5 atoms in Hg2Cl2: 2 mercury atoms (Hg) and 3 chlorine atoms (Cl).
The molar mass of mercury (Hg) is 200.59 g/mol. In 200.6g, there would be 1 mole of Hg, which is equal to 6.022 x 10^23 atoms. In 400.1g, there would be 2 moles of Hg, which is equal to 1.2044 x 10^24 atoms.
55.8 grams
0.3173 moles Hg (6.022 X 1023/1 mole Hg) = 1.912 X 1023 atoms of mercury =======================
There are five atoms in Hg2SCl2: 2 atoms of mercury (Hg), 1 atom of sulfur (S), and 2 atoms of chlorine (Cl).
2Hg atoms and 2Cl atoms for a total of 4 atoms.
One part of one mole of anything (eg. atoms in a mole atoms) is 1 / (6*10+23) = 1.6*10-24
grams of mercury (Hg) 1 mole x 1 mole Avogadro's number (6.022 x 1023) of atoms 200.6 grams Hg 1 mole 200.6 grams Hg = x = ≈ 3.3311192-23 atoms Hg 1 mole 6.022 x 1023 atoms 6.022 x 1023 atoms
To convert Torr to mm Hg, divide by 1.33. So, the partial pressure of helium in mm Hg is 439 Torr / 1.33 = 330 mm Hg. To find the partial pressure of hydrogen, subtract the partial pressure of helium from the total pressure: 600 mm Hg - 330 mm Hg = 270 mm Hg. Hence, the partial pressure of hydrogen gas is 270 mm Hg.
To find the number of atoms in 22.9 moles of mercury (Hg), you can use Avogadro's number, which is approximately (6.022 \times 10^{23}) atoms per mole. Multiply the number of moles by Avogadro's number: [ 22.9 , \text{mol} \times 6.022 \times 10^{23} , \text{atoms/mol} \approx 1.38 \times 10^{25} , \text{atoms}. ] Therefore, there are approximately (1.38 \times 10^{25}) atoms in 22.9 moles of Hg.
No Hg, or mercury is an element, but it is not molecular.
Mercury (Hg) forms a Hg-Hg bond because it is a liquid metal at room temperature with weak interatomic forces. This allows the mercury atoms to come close together and form a weak bond due to the sharing of electrons.