There are 6.022 × 1023 atoms of potassium in every mole of potassium. Since one mole of KOH contains one mole of K, the answer is 6.022×1023 atoms of K.
Therefore, 3.5 moles * 6.022E23 atoms/1 mole= 2.107E24
350 g sample of CO contain 12,49 moles.
To find the mass of 350 mol of bromine, you need to multiply the number of moles by the molar mass of bromine. The molar mass of bromine is approximately 79.9 g/mol. So, 350 mol * 79.9 g/mol = 27965 g. Therefore, the mass of 350 mol of bromine is 27965 grams.
Molarity = moles of solute/Liters of solution. ( 350 ml = 0.350 Liters ) 5.7 M NaOH = moles NaOH/0.350 Liters = 1.995 moles NaOH (39.998 grams/1 mole NaOH) = 78 grams NaOH needed ------------------------------------
A 1 M (molar) solution of glucose contains 1 mole of glucose per liter (1000 ml). Therefore, in 350 ml of a 1 M glucose solution, there are 0.35 moles of glucose. The molar mass of glucose (C6H12O6) is approximately 180 g/mol, so the amount of glucose in 350 ml is 0.35 moles × 180 g/mol = 63 grams.
Answer: 350 mi² = 224,000 acres
350 g sample of CO contain 12,49 moles.
To convert grams to moles you need the molecular mass. Firstly you need to convert 350 picomoles to micromoles. 350/1,000,000 is 0.000350 micromoles. Then you multiply by the molecular weight of the compound.
To find the number of moles in 350g of sodium, divide the given mass by the molar mass of sodium. The molar mass of sodium is approximately 23g/mol. Therefore, 350g of sodium is equal to 350/23 = 15.22 moles.
To find the mass of 350 mol of bromine, you need to multiply the number of moles by the molar mass of bromine. The molar mass of bromine is approximately 79.9 g/mol. So, 350 mol * 79.9 g/mol = 27965 g. Therefore, the mass of 350 mol of bromine is 27965 grams.
Divide 4.2x1024 by 6.022x1023 to get the number of moles.The second number is Avogadro's constant, it represents the number of atoms in one mole of any substance.So if you have X number of atoms given, and you are asked to find how many moles that is equal to just divide by Avagadro's constant to get the answer.For this: it is 6.974 if you forget about sigdigs.Rounded to the real number of sgnificant digits the answer is 7.0 mol of N-atoms or 3.5 mol of N2molecules.
To find the grams of Na2SO4 needed, you first need to calculate the number of moles using the molarity formula: moles = Molarity x Volume (in liters). Then, use the molar mass of Na2SO4 (142.04 g/mol) to convert moles to grams. In this case, you would need 35.25 grams of Na2SO4 to make 350 ml of 0.5M solution.
To calculate the grams of NaOH in the solution, first determine the moles of NaOH using the molarity and volume. Then, convert moles to grams using the molar mass of NaOH. The molar mass of NaOH is 40 g/mol.
350 of them.
Molarity = moles of solute/Liters of solution. ( 350 ml = 0.350 Liters ) 5.7 M NaOH = moles NaOH/0.350 Liters = 1.995 moles NaOH (39.998 grams/1 mole NaOH) = 78 grams NaOH needed ------------------------------------
A 1 M (molar) solution of glucose contains 1 mole of glucose per liter (1000 ml). Therefore, in 350 ml of a 1 M glucose solution, there are 0.35 moles of glucose. The molar mass of glucose (C6H12O6) is approximately 180 g/mol, so the amount of glucose in 350 ml is 0.35 moles × 180 g/mol = 63 grams.
350 ml = 350 cc
350 ÷ 50 = 7