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How many grams of sodium are there in 10.0 grams of sodium sulfate?
Na2SO4 10.0 grams Na2SO4 (1 mole Na2SO4/142.05 grams)(2 mole Na/1 mole Na2SO4)(22.99 grams/1 mole Na) = 3.24 grams of sodium -------------------------------
How many grams of sodium sulfate will be formed if you start with 12.5 grams of sodium hydroxide and you have an excess of sulfuric acid?
Balanced equation. 2NaOH + H2SO4 -> Na2SO4 + 2H2O 12.5 grams NaOH (1 mole NaOH/39.998 grams)(1 mole Na2SO4/2 mole NaOH)(142.05 grams/1 mole Na2SO4) = 22.2 grams sodium sulfate produced ===========================
How many grams of sodium sulfate will be formed if you start with 200grams of sodium hydroxide and you have an excess of sulfuric acid?
First write down the BALANCED reaction equation. 2NaOH + H2SO4 = Na2SO4 + 2H2O Note the molar ratios are 2:1::1:2 So two moles of NaOH produces one mole of Na2SO4 Next calculate tghe moles of NaOH mol(NaOH) = 200/(23 + 16 + 1) = 200/40 = 5 mol(NaOH) = 5 (This figure is equivalent to '2' above) mol(Na2SO4) = 5/2 = 2.5 ( Equivalent to '1' above) mol(Na2SO4) ; 2.5 = mass(g) / (2 x 23) + 32 + (4 x 16)) 2.5 = mass(g) / 142) mass*Na2SO4) = 2.5 x 142 = 355 g
How do you the stoichiometry problem 2 NaOH plus H2SO4---2 H2O plus Na2SO4how many grams of sodium sulfate will be formed if you start with 200 grams of sodium hydroxide and you have an excessofsulfur?
To solve this stoichiometry problem, first calculate the number of moles of sodium hydroxide (NaOH) present in 200 grams. Then, using the balanced equation, determine the moles of sodium sulfate (Na2SO4) that will be formed. Finally, convert the moles of Na2SO4 to grams using the molar mass of sodium sulfate.
How many grams of sodium sulfate are required to prepare a 350 mL solution whose concentration is 0.683 M?
Amount of sodium sulfate required = 0.683 x 350/100 = 0.239The formula mass of sodium sulfate, Na2SO4 is 2(23.0) + 32.1 + 4(16.0) = 142.1 Therefore mass of sodium sulfate required = 0.239 x 142.1 = 34.0g Approximately 34 grams of sodium sulfate would be needed.
How many grams of HCl are needed to make 21.5 grams of Na2SO4?
Sodium sulfate is not prepared from hydrogen chloride.
How many grams are in 3.6 moles of sodium sulfate?
3.6 moles N2SO4 (142.05 grams/1 mole Na2SO4) = 511.38 grams Na2SO4 ==================( you do significant figures )
How many grams of sodium are there in 10.0 grams of sodium sulfate?
Na2SO4 10.0 grams Na2SO4 (1 mole Na2SO4/142.05 grams)(2 mole Na/1 mole Na2SO4)(22.99 grams/1 mole Na) = 3.24 grams of sodium -------------------------------
How many moles of Na SO4 are in 25.0 of this compound?
To find the number of moles of Na2SO4 in 25.0 g of the compound, you need to convert the mass to moles. First, determine the molar mass of Na2SO4, then divide the given mass by the molar mass to obtain the number of moles.
How many grams of Na+are contained in 25 g of sodium sulfate (Na2SO4)?
To find the mass of Na+ in sodium sulfate (Na2SO4), we need to consider the molar ratios of Na+ in the compound. In Na2SO4, there are 2 Na+ ions for every 1 Na2SO4 unit. The molar mass of Na2SO4 is 142 g/mol, so in 25 g of Na2SO4, there are about 8.8 g of Na+.
How many grams of sodium are there in 10 g of sodium sulfate Na2SO4?
There are 2.42 grams of sodium in 10 grams of sodium sulfate (Na2SO4). This is calculated based on the molecular weight of sodium sulfate and the molar ratio of sodium to the sulfate ion in the compound.
How many grams of sodium sulfate will be formed if you start with 12.5 grams of sodium hydroxide and you have an excess of sulfuric acid?
Balanced equation. 2NaOH + H2SO4 -> Na2SO4 + 2H2O 12.5 grams NaOH (1 mole NaOH/39.998 grams)(1 mole Na2SO4/2 mole NaOH)(142.05 grams/1 mole Na2SO4) = 22.2 grams sodium sulfate produced ===========================
How many grams of sodium are in 0.820 moles of Na2SO4?
To find the grams of sodium in 0.820 moles of Na2SO4, first calculate the molar mass of Na2SO4: 2(Na) + 1(S) + 4(O) = 2(23) + 32 + 4(16) = 142 g/mol. Since each mole of Na2SO4 contains 2 moles of Na atoms, the molar mass of Na in Na2SO4 is 46 g/mol. Therefore, in 0.820 moles of Na2SO4, there are 0.820 moles * 2 moles Na * 46 g/mol = 75.32 grams of sodium.
How many gram gold require to make a gold ring?
2-3 grams is typically required.
How many grams of solid barium sulfate form when 22.6 mL of 0.160 M barium chloride reacts with 54.6 mL of 0.055 M sodium sulfate?
Balanced equation first. BaCl2 + Na2SO4 -> 2NaCl + BaSO4 22.6 ml BaCl2 = 0.0226 liters 54.6 ml Na2SO4 = 0.0546 liters 0.160 M BaCl2 = moles BaCl2/0.0226 liters = 0.00362 moles BaCl2 0.055 M Na2SO4 = moles Na2SO4/0.0546 liters = 0.0030 moles Na2SO4 The ratio of BaCl2 to Na2SO4 is one to one, so either mole count wull drive this reaction. Use 0.0003 moles Na2SO4 0.0030 moles Na2SO4 (1 mole BaSO4/1 mole Na2SO4)(233.37 grams/1 mole BaSO4) = 0.700 grams of BaCO4 produced
How many grams of sodium sulfate will be formed if you start with 200grams of sodium hydroxide and you have an excess of sulfuric acid?
First write down the BALANCED reaction equation. 2NaOH + H2SO4 = Na2SO4 + 2H2O Note the molar ratios are 2:1::1:2 So two moles of NaOH produces one mole of Na2SO4 Next calculate tghe moles of NaOH mol(NaOH) = 200/(23 + 16 + 1) = 200/40 = 5 mol(NaOH) = 5 (This figure is equivalent to '2' above) mol(Na2SO4) = 5/2 = 2.5 ( Equivalent to '1' above) mol(Na2SO4) ; 2.5 = mass(g) / (2 x 23) + 32 + (4 x 16)) 2.5 = mass(g) / 142) mass*Na2SO4) = 2.5 x 142 = 355 g
How many toothpicks equal 40 grams?
The weight of a toothpick can vary, but on average, one toothpick weighs about 0.25 grams. Therefore, 160 toothpicks would be required to make up 40 grams.
