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For this problem you don't need the Atomic Mass of the element. If you want to convert moles to atoms, you need to take the number of moles and multiply it by Avogadro's constant, 6.02 × 1023. Divide by one mole for units to cancel.
9.00 moles C × (6.02 × 1023 atoms) = 5.42 × 1024 atoms C
What else can I help you with?
How many atoms are present in 8.00 mol atoms?
48,177 134 32.1023 atoms
How many hydrogen atoms are in 0.63 mol of (NH4)2SO4?
0.63 mol of (NH4)2SO4 contain 3,978.10e23 hydrogen atoms.
How many atoms found in 0.75 mol Ag?
To find the number of atoms in 0.75 mol of silver (Ag), you can use Avogadro's number, which is approximately (6.022 \times 10^{23}) atoms/mol. Multiply 0.75 mol by Avogadro's number: [ 0.75 , \text{mol} \times 6.022 \times 10^{23} , \text{atoms/mol} \approx 4.51 \times 10^{23} , \text{atoms}. ] Thus, there are approximately (4.51 \times 10^{23}) atoms in 0.75 mol of silver.
How many atoms of phosphorus are in 8.90 mol of copperII phosphate?
To find the number of phosphorus atoms in 8.90 mol of copper(II) phosphate (Cu₃(PO₄)₂), we first identify that each formula unit contains 2 phosphorus (P) atoms. Thus, in 8.90 mol of copper(II) phosphate, the total number of phosphorus atoms is calculated as follows: 8.90 mol × 2 P/mol = 17.8 mol of phosphorus atoms. To convert moles to atoms, we multiply by Avogadro's number (approximately (6.022 \times 10^{23}) atoms/mol): 17.8 mol × (6.022 \times 10^{23}) atoms/mol ≈ (1.07 \times 10^{24}) phosphorus atoms.
How many mole of atoms are there in 9g of Aluminium?
To find the number of moles of atoms in 9 grams of aluminum, you can use the molar mass of aluminum, which is approximately 27 g/mol. Dividing the mass of aluminum (9 g) by its molar mass (27 g/mol) gives you about 0.33 moles of aluminum. Since each aluminum atom is a single atom, there are also 0.33 moles of atoms in 9 grams of aluminum.
How many atoms of sodium na are in 7 mol of sodium answer in units of atoms?
the constant Mole (mol): 6.02 x 10^23 are how many atoms you have per mol so the answer can be 7 mol atoms or 6.02 x 10^23 atoms per mol x 7 actual answer is 4.214 X10^24 atoms in 7 mol
How many atoms are present in 80.0 mol of zirconium?
To determine the number of atoms in 80.0 mol of zirconium, you can use Avogadro's number, which is 6.022 x 10^23 atoms/mol. Multiply 80.0 mol by Avogadro's number to find the total number of atoms in 80.0 mol of zirconium.
How many atoms are in 0.0077 mol C?
There are approximately 4.65 x 10^22 atoms in 0.0077 mol of carbon.
How many atoms of oxygen are in 0.50 mol of CaNO32?
The answer is 18,061.1023 atoms.
How many sulfur atoms are in 0.45 mol BaSO4?
There are 0.45 mol of BaSO4. In one mole of BaSO4, there is one sulfur atom. Therefore, there are 0.45 mol of sulfur atoms in 0.45 mol of BaSO4.
How many atoms are present in 8.00 mol atoms?
48,177 134 32.1023 atoms
How many hydrogen atoms are there in 0.5 mole of Hydrogen?
Avagadro's number = 6.022 × 1023 atoms/mol0.5 mol × (6.022 × 1023) atoms/mol = 3.011 ×1023 atoms
How many hydrogen atoms are in 0.63 mol of (NH4)2SO4?
0.63 mol of (NH4)2SO4 contain 3,978.10e23 hydrogen atoms.
How many atoms do six grams of diamond have?
Diamond is made of up carbon. So, it has a molar mass of 12 g/mol. 6 g/mol / 12 g = 0.5 mol 0.5 mol * 6x10^23 atoms/mol = 3x10^23 atoms There are 3x10^23 atoms in six grams of diamond.
How many atoms are contained in 2.23 mol C2H6?
107,43.10e+23 atoms
A small pin contains 0.0178 mol of iron how many atoms of iron are in the pin?
To calculate the number of iron atoms in 0.0178 mol of iron, you can use Avogadro's number, which is 6.022 x 10^23 atoms/mol. Number of iron atoms = 0.0178 mol x 6.022 x 10^23 atoms/mol = 1.07 x 10^22 atoms.
How many atoms are present in 104 mol of tungsten?
no
