To find the number of atoms in 179.0 g of iridium (Ir), first determine its molar mass, which is approximately 192.22 g/mol. Next, calculate the number of moles in 179.0 g by dividing the mass by the molar mass: 179.0 g / 192.22 g/mol ≈ 0.933 moles. Finally, multiply the number of moles by Avogadro's number (approximately (6.022 \times 10^{23}) atoms/mol) to find the total number of atoms: (0.933 \text{ moles} \times 6.022 \times 10^{23} \text{ atoms/mol} \approx 5.61 \times 10^{23}) atoms.
To find the number of atoms in 179.0 g of iridium, first determine the molar mass of iridium, which is approximately 192.22 g/mol. Then, calculate the number of moles in 179.0 g by dividing the mass by the molar mass: ( \text{moles} = \frac{179.0 , \text{g}}{192.22 , \text{g/mol}} \approx 0.93 , \text{mol} ). Finally, multiply the number of moles by Avogadro's number (( 6.022 \times 10^{23} , \text{atoms/mol} )) to find the total number of atoms: ( 0.93 , \text{mol} \times 6.022 \times 10^{23} \approx 5.59 \times 10^{23} , \text{atoms} ).
There are 10 hydrogen atoms present in 4C2H5OH.
26,4 g iridium is equal to 0,137 mol.
48,177 134 32.1023 atoms
2
To find the number of atoms in 179.0 g of iridium, first determine the molar mass of iridium, which is approximately 192.22 g/mol. Then, calculate the number of moles in 179.0 g by dividing the mass by the molar mass: ( \text{moles} = \frac{179.0 , \text{g}}{192.22 , \text{g/mol}} \approx 0.93 , \text{mol} ). Finally, multiply the number of moles by Avogadro's number (( 6.022 \times 10^{23} , \text{atoms/mol} )) to find the total number of atoms: ( 0.93 , \text{mol} \times 6.022 \times 10^{23} \approx 5.59 \times 10^{23} , \text{atoms} ).
There are 10 hydrogen atoms present in 4C2H5OH.
26,4 g iridium is equal to 0,137 mol.
48,177 134 32.1023 atoms
The number of atoms is indicated by coefficients.
There are 3 oxygen atoms present in sodium chlorate (NaClO3).
The total no. of atoms present in C12H22O11 is 45.
2
There are two chiral carbon atoms present in 2,3,4-trichloropentane.
The chemical formula of propane is C3H8; 11 atoms are present in the molecule.
Approx. 9.1024 atoms.
48,177 134 32.1023 atoms