The total no. of atoms present in C12H22O11 is 45.
45 in one molecule.
One. One hydrogen, one nitrogen, and 3 oxygen (notice the 3 in subscript after the O).
That's a total of four atoms... 1 of Hydrogen, 1 Nitrogen and 2 Oxygen.
There are three different types of elements in glucose: Carbon, Hydrogen, and Oxygen. With a formula, C6H12O6, there are a total of 24 atoms.
6. 2 sodium, 1 carbon, and 3 oxygen.
Molar mass of Fe(NO3)2 is 55.85 + 2(14.00 + 3(16.00)) = 179.85 g/mol Therefore, number of moles of Fe(NO3)2 present is 53.55/179.85 = 0.2977 mol For each molecule of Fe(NO3)2, there are two atoms of nitrogen associated with it. Therefore, there are 0.2977*2 = 0.5954 mol of nitrogen atoms
12
135. The empirical formula for sucrose (table sugar) is C12H22O11, for 45 atoms per sucrose molecule.
11
The chemical formula for maltose is C12H22O11, so there are a total of 12 carbon atoms in a molecule of maltose. A molecule of maltose has 11 oxygen atoms, not 12.
12+22+11=45
There are eleven oxygen atoms in a molecule of table sugar C12H22O11.
The chemical formula for maltose is C12H22O11, so there are a total of 12 carbon atoms in a molecule of maltose. A molecule of maltose has 11 oxygen atoms, not 12.
The chemical formula for maltose is C12H22O11, so there are a total of 12 carbon atoms in a molecule of maltose. A molecule of maltose has 11 oxygen atoms, not 12.
The grams of Carbon present in C12H22O11 depends on how many grams of C12H22O11 you have. For every 342 grams of C12H22O11 that you have, you will have 12 g of carbon.
The formula with this disaccharide is, C12H22O11 17.1 grams C12H22O11 (1 mole C12H22O11/342.296 grams)(11 mole O/1 mole C12H22O11)(6.022 X 10^23/1 mole O) = 3.31 X 10^23 atoms of oxygen ------------------------------------------
10 pounds C12H22O11 (454 grams/1 pound)(1 mole C12H22O11/342.296 grams)(12 mole C/1 mole C12H22O11)(6.022 X 1023/1 mole C) = 9.6 X 1025 atoms of carbon =====================
Maltose is a disaccharide with the formula C12H22O11.