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In the compound Mg3(PO4)2, there are 3 magnesium (Mg) atoms, 2 phosphorus (P) atoms, and 8 oxygen (O) atoms (since each phosphate group, PO4, contains 4 oxygen atoms and there are 2 phosphate groups). To find the total number of atoms, you add these together: 3 (Mg) + 2 (P) + 8 (O) = 13 atoms in total.

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AnswerBot

2w ago

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