To find the number of hydrogen-1 atoms in a 1.007-g sample, first note that the molar mass of hydrogen-1 is approximately 1.007 g/mol. This means that 1.007 grams of hydrogen-1 corresponds to 1 mole of hydrogen atoms. Since one mole of any substance contains approximately (6.022 \times 10^{23}) atoms (Avogadro's number), a 1.007-g sample of hydrogen-1 contains about (6.022 \times 10^{23}) atoms.
A 88,1 gram sample of Ag contain 4,9185.10e23 atoms.
The number of atoms is 1,50553521.10e23.
Take the actual sample weight of 13grams, and divide it by the atomic weight of chromium. This gives you your molar percentage of atoms. Now multiply this molar percentage by Avogadro's constant, the number of atoms in one mole, and this will give you your number of atoms in the sample.
This depends on the mass of the gold sample.
Your question does not make sense. One sample of bohrium could have a certain amount of atoms, while another sample of bohrium may have a different number of atoms. You probably mean: How many protons does bohrium have? Although it is synthetic and radioactive, a bohrium atom can be retained for a few seconds. It then has 107 protons.
A 88,1 gram sample of Ag contain 4,9185.10e23 atoms.
After 10740 years, half of the sample would have decayed, so there would be 200 atoms left. If the original sample had 400 atoms, then there would be 200 atoms left in the sample after 10740 years.
The number of atoms is 1,50553521.10e23.
There are approximately 6 x 10^22 atoms in a 12.0 gram sample of sodium.
Approx. 9.1024 atoms.
Take the actual sample weight of 13grams, and divide it by the atomic weight of chromium. This gives you your molar percentage of atoms. Now multiply this molar percentage by Avogadro's constant, the number of atoms in one mole, and this will give you your number of atoms in the sample.
This depends on the mass of the gold sample.
The answer is 6,2729.10e+26 carbon atoms.
To calculate the number of sodium atoms in the sample, first find the number of moles in the sample by dividing the mass (8.2 g) by the molar mass of sodium (22.99 g/mol). Then, use Avogadro's number (6.022 x 10^23 atoms/mol) to convert moles to atoms. Therefore, there are approximately 2.71 x 10^23 sodium atoms in a sample weighing 8.2 grams.
Your question does not make sense. One sample of bohrium could have a certain amount of atoms, while another sample of bohrium may have a different number of atoms. You probably mean: How many protons does bohrium have? Although it is synthetic and radioactive, a bohrium atom can be retained for a few seconds. It then has 107 protons.
There are 57.6 grams of tin in that sample.
To find the number of argon atoms in a 40.0-g sample, you first need to calculate the number of moles of argon in the sample using the molar mass of argon (39.95 g/mol). Then, you can use Avogadro's number (6.022x10^23 atoms/mol) to determine the number of atoms in that many moles of argon.