0.035mol. Apply to PV=nRT
the atomic mass of FeS2 is 110. You cannot find the no. of moles in a mole of FeS2 coz it is only a mole.
(2.7 mol Ca / 1) * (40.078 g Ca / 1 mol Ca) = 108.21 g Ca. After significant figures, the answer is 110 g Ca.
True. To calculate the molarity, you need to divide the moles of solute by the volume of solution in liters. First, convert 110 g of HC2H3O2 to moles using its molar mass. Then, divide the moles by 1.25 L to get the molarity, which in this case is 1.47 M.
The atomic mass of Potassium is 39 and that of Sulfur 32. The formula for Potassium Sulfide is K2S therefore the molecular weight of Potassium Sulfide is (39 * 2) + 32 = 110. Therefore one mole of Potassium Sulfide weighs 110 grams. Therefore 3.3 moles of Potassium Sulfide weigh 110 * 3.3 = 363 grams.
To find the number of atoms in 110 grams of CO2, you first need to determine the number of moles by dividing the mass by the molar mass of CO2 (44.01 g/mol). Next, you can use Avogadro's number (6.022 x 10^23 atoms/mol) to convert moles to atoms. So, there are approximately 2.5 x 10^24 atoms in 110 grams of CO2.
The volume is 4908 L at oC.
2H2 + O2 --> 2H2OAs you can see by the balanced reaction, for every 1 mole of oxygen used, 2 moles of water are formed. Also notice that for every 1 mole of oxygen used, you need 2 moles of hydrogen to produce the 2 moles of water. So in your case 110 moles of oxygen would produce 220 moles of water & would also require 220 moles of hydrogen (which you have in excess since you have 230 moles of hydrogen). So 220 moles of water are the most that can be formed.
the Atomic Mass of FeS2 is 110. You cannot find the no. of moles in a mole of FeS2 coz it is only a mole.
0.035mol. Apply to PV=nRT
the atomic mass of FeS2 is 110. You cannot find the no. of moles in a mole of FeS2 coz it is only a mole.
To find the number of moles of KBr in the solution, first convert the volume to liters (110mL = 0.110L). Then, use the formula: moles = molarity x volume in liters. So, moles of KBr = 0.290 mol/L x 0.110 L = 0.032 moles of KBr.
(2.7 mol Ca / 1) * (40.078 g Ca / 1 mol Ca) = 108.21 g Ca. After significant figures, the answer is 110 g Ca.
True. To calculate the molarity, you need to divide the moles of solute by the volume of solution in liters. First, convert 110 g of HC2H3O2 to moles using its molar mass. Then, divide the moles by 1.25 L to get the molarity, which in this case is 1.47 M.
The atomic mass of Potassium is 39 and that of Sulfur 32. The formula for Potassium Sulfide is K2S therefore the molecular weight of Potassium Sulfide is (39 * 2) + 32 = 110. Therefore one mole of Potassium Sulfide weighs 110 grams. Therefore 3.3 moles of Potassium Sulfide weigh 110 * 3.3 = 363 grams.
To find the molarity of Cl in the solution, first calculate the number of moles of CaCl2 using its molar mass. Then, since each formula unit of CaCl2 contains 2 moles of Cl, multiply the moles of CaCl2 by 2 to get moles of Cl. Finally, divide moles of Cl by the volume of the solution in liters to find the molarity.
seriousely? 110