10.8 grams silver (1 mole Ag/107.9 grams)(6.022 X 1023/1 mole Ag)
= 6.03 X 1022 atoms of silver
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108g is 0.238 pound.
One formula unit of silver sulfate, Ag2SO4 has 7 atoms.
5 :)
A dozen is equal to 12, so there are 12 x 6.022 x 10^23 silver atoms in a mole. The number of dozens of silver atoms in the piece of jewelry would depend on the weight of the jewelry and the molar mass of silver.
The chemical formula for silver chlorate is AgClO3. To determine the number of atoms in silver chlorate, we must consider the subscripts in the formula. There is 1 silver atom (Ag), 1 chlorine atom (Cl), and 3 oxygen atoms (O) in each molecule of silver chlorate. Therefore, there are a total of 5 atoms in one molecule of silver chlorate.
To calculate the number of moles in 108g of silver, you need to divide the mass of silver by its molar mass. The molar mass of silver is approximately 107.87 g/mol. Dividing 108g by the molar mass gives you around 1 mole of silver.
1 mole of silver contains Avogadro's number of silver atoms, while 1 mole of gold contains Avogadro's number of gold atoms. The molar mass of silver and gold can be used to determine the mass of each element in 1 mole. Both contain the same number of atoms per mole due to Avogadro's number.
Silver is an atom.
108g is 0.238 pound.
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A mole of silver contains approximately 6.022 x 10^23 atoms.
There are 6.022x1023 atoms in a mole. You multiply 6.022x1023 by 8.68, which equals 52.20796x1023 atoms
One formula unit of silver sulfate, Ag2SO4 has 7 atoms.
There are 5 atoms in silver nitrate (1 silver, 1 nitrogen and 3 oxygens).
2.26*1024
2.17*10^22
5 :)