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How many btu must be removed from one pound of water at 200F for it to end as ice at 30F?

To calculate the heat energy required to cool water from 200°F to 32°F (its freezing point) and then to further cool it to 30°F and freeze it, we need to consider the specific heat capacities and latent heat of fusion of water. The specific heat capacity of water is 1 BTU/lb°F, and the latent heat of fusion of water is 144 BTU/lb. To cool water from 200°F to 32°F, we need to remove: (200°F - 32°F) * 1 BTU/lb°F = 168 BTU. To freeze the water at 32°F, we need to remove the latent heat of fusion: 144 BTU. Therefore, the total heat energy required to cool one pound of water from 200°F to ice at 30°F is 168 BTU + 144 BTU = 312 BTU.


How much would a 200 pound person weigh on planet mars?

200 pound person would weight about 75 pound on planet Mar, by Lal N, Siama


How many Btus must be removed from one pound of water at 200f fro it to end up as ice at 30f?

To determine the BTUs that must be removed from one pound of water at 200°F to convert it to ice at 30°F, we need to account for several steps: cooling the water from 200°F to 32°F (the freezing point), the phase change from water to ice at 32°F, and then cooling the ice from 32°F to 30°F. Cooling the water from 200°F to 32°F requires about 168 BTUs (1 BTU cools 1 pound of water by 1°F). Freezing the water at 32°F requires the removal of 80 BTUs (latent heat of fusion). Cooling the ice from 32°F to 30°F requires an additional 2 BTUs. In total, approximately 250 BTUs must be removed (168 + 80 + 2 = 250 BTUs).


How many Btus must be removed from 1lb of water at 200F for it end up as ice at 30F?

To convert 1 lb of water at 200°F to ice at 30°F, you need to remove 233 BTUs. This involves cooling the water from 200°F to 32°F (latent heat of fusion) and then further cooling the ice from 32°F to 30°F.


What would a 200 pound person weigh on Pluto?

A 200 pound person on Earth would weigh about 71 pounds on Pluto due to the lower gravity on Pluto compared to Earth.

Related Questions

How many btu's must be removed from one pound of water at 200f for it to end up as ice at 30f?

To convert water at 200°F to ice at 30°F, you need to remove 1 BTU to cool water from 200°F to 32°F to become ice. Then, you need to remove 144 BTUs to cool the ice from 32°F to 30°F. So, total BTUs needed to remove from one pound of water at 200°F to end up as ice at 30°F is 144 + 1 = 145 BTUs.


How many pound of water would be found in a person who weighs 200 pounds?

75


How many btus must be removed from one pound of water at 200 for it to end up as ice at 30?

144


How many pennies are in a 2 pound?

200


How many pence in 2 pound?

200


How many is is 91 kilograms?

200 pounds91 kilogrqam into pound 91 kilogrqam into pound


How many pound are in 3200 oz?

200 pounds.


How many Btu's must be removed from one pound of water at 200 degrees Fahrenheit for it to end up as ice at 30 degrees Fahrenheit?

To change water at 200°F to ice at 30°F, you need to remove 144 Btu from one pound of water. This process involves cooling the water to its freezing point of 32°F, then removing the latent heat of fusion to convert it to ice at 32°F, and finally further cooling the ice to the desired temperature of 30°F.


A 200-pound man carries about how many pounds of water?

Well, honey, a 200-pound man is carrying around approximately 120 pounds of water. Our bodies are about 60% water, so you do the math. Just remember, staying hydrated is key, but maybe hit the gym too if you're feeling a little heavy on the scale.


How many oz in a 12.5 pound turkey?

200 ounces.


200 lbs is how many ounces?

there is 16 ounces in a pound so in 200 pounds there is 3,200 ounces


How many BTUs must be removed from one pound of water at 200 F for it to end up as ice at 30 F?

actually its 313.