Helium (He) and Calcium (Ca) both have 2 valence electrons.
The calcium atom (Ca) loses two valence electrons to form a calcium ion (Ca2+).
Calcium has 2, 8, 8, and 2 electrons in its shells. The particulars are here: http://en.wikipedia.org/wiki/Calcium
Calcium is in group 2 of the periodic table, meaning that it has 2 electrons in its (outer) valence shell. So it 'only' has to lose those 2 electrons from that to acquire Argon's noble gas structure Ar(2,8,8)Ca(2,8,8,2) --> Ca(2,8,8,0)2+ + 2e-
Ca has 2 electrons in its valence shell. When ionized, it transfers its 2 extra electrons to another atom in order to stabalize its outer shell. Therefore, it is losing 2 negatively charged particles and gains a charge of "2+".
Two electrons are donated by Calcium to an oxidant (nonmetal, eg. O2) by which calcium gets oxidised.Ca --> Ca2+ + 2e-This is because Ca is in group 2 of the periodic system, belonging to the 'earth alkali' metals and so it has 2 electrons (2e-) in its valency (or outer) shell (2,8,8,2). Hence Ca2+ configuration is (2,8,8,-), with an empty (-) 4th shell (the 'N' shell) like Argon. Ca3+ would have the (2,8,7,-) configuration, which is energetically impossible, it is not a 'noble gas' configuration. Sc3+ (with one more proton) can have this: 2,8,8,-configuration.
Ca has 2 electrons in its outermost shell its configuration being 2, 8,8,2 or 1s2, 2s2, 2p6, 3s2 3p6, 4s2 (4s2 fills before 3d becuase of the aufbau principle) He has also got two electrons these fill the first energy level resulting in a stable arrangement. 1s2
Ca has 20 so 1s22s22p63s23p64s2 so it has 2 He is 1s2 so it has 2 as well
The calcium atom (Ca) loses two valence electrons to form a calcium ion (Ca2+).
Calcium typically loses 2 electrons to form a stable ion with a 2+ charge. This is because calcium has 2 electrons in its outer shell, and it is energetically favorable for it to lose these electrons to achieve a full outer shell configuration.
Cl-Cr-Cl
Calcium (Ca) typically loses 2 electrons to become more stable when bonding, as it has 2 valence electrons in its outer shell. By losing these electrons, calcium achieves a full octet, making it more stable.
Yes, the outer electron configuration of Ca before the reaction (2,8,8,2) is stable due to having a full outermost shell. This stability is a result of the octet rule, which states that atoms tend to gain, lose, or share electrons to achieve a full outer shell of electrons.
Calcium has 2, 8, 8, and 2 electrons in its shells. The particulars are here: http://en.wikipedia.org/wiki/Calcium
Na, Rb, Al3+, and S2- do not have a noble gas configuration as they do not have the complete outer shell of electrons like a noble gas. O2, Br, Ca, and O2- have noble gas configurations as they either have a complete outer shell of electrons or have gained/lost electrons to achieve a stable noble gas configuration.
6 electrons in Ca are core electrons: 1s2,2s2,2p6,3s2,3p6,4s2 For every complete orbital, there is a core electron. There are a total of 18 core electrons in Ca. Also, there are 2 valence electrons in Ca. The valence electrons are the electrons that are in the outmost most shell, which will be the fourth shell.
CaS Because Calcium has 2 electrons in its outer shell- so it needs to get rid of those (Ca2+) Sulfur has 6 electrons in its outer shell- so it needs 2 more to have a full outer shell (S2-)
Ca has 2 electrons in outer shell (valence electrons) and O has six. Because of this, Ca loses 2 electrons which O gains, and Ca becomes a Ca2+ ion, and O becomes an O2- ion. These then bond to form CaO. Ca2+ + O2- → CaO