two.
Al4C3
The halogens, forming aluminium trihalides, oxygen, sulfur and selenium, forming Al2O3 Al2S3, Al2Se3 Nitrogen and phosphorus, forming AlN and AlP Carbon forming Al4C3
The bond in Al4C3 is ionic, with aluminum (Al) forming cations and carbon (C) forming anions. Aluminum loses electrons to become positively charged, while carbon gains electrons to become negatively charged, resulting in the formation of an ionic bond between Al and C atoms.
103
There are two elements, carbon and hydrogen.
Al4C3
Its Aluminium silicide
The halogens, forming aluminium trihalides, oxygen, sulfur and selenium, forming Al2O3 Al2S3, Al2Se3 Nitrogen and phosphorus, forming AlN and AlP Carbon forming Al4C3
The balanced equation is: 4Al₄C₃ + 12H₂O → 4Al(OH)₃ + 3CH₄. This equation is balanced by ensuring that the number of each type of atom is the same on both sides of the equation.
The bond in Al4C3 is ionic, with aluminum (Al) forming cations and carbon (C) forming anions. Aluminum loses electrons to become positively charged, while carbon gains electrons to become negatively charged, resulting in the formation of an ionic bond between Al and C atoms.
The oxidation number of carbon (C) in Al4C3 is -4. This is because aluminum (Al) has an oxidation number of +3 and there are 4 aluminum atoms for a total oxidation number of +12. This must be balanced by the oxidation numbers of the carbon atoms, which must be -4 in order for the compound to be neutral.
Aluminum carbide contains two different kinds of atoms: aluminum and carbon. The formula unit or molecular formula for aluminum carbide is Al4C3.
118 elements
Al4C3 + 12 H2O → 4 Al(OH)3 + 3 CH4When aluminum carbide reacts with water, methane is formed.
There are 118 elements on the periodic table.
92 elements
NaCl has two elements: sodium (Na) and chlorine (Cl).