2.430g. That's one tenth the number of grams in one mole of Mg, which would be 24.30, which is also its atomic weight. No, that is not a coincidence. Atomic weight of an element is always equal to the number of grams of an element in a mole of the same element.
800 g oxygen are needed.
1 kilogram = 1000 grams. You now have all the information required to work out, for yourself, the answer to this and similar questions.
C3H8 + 5O2 --> 3CO2 + 4H2O 2.75 mole C3H8 (5 moles O2/1 mole C3H8)(32 grams/1 moleO2) = 440 grams oxygen required =====================
999 g
1 cup = 226,79 grams / 226,79 grams = 1 cup
To calculate the number of grams of C6H12O6 needed to form 7.50g of C2H5OH, you need to consider the stoichiometry of the reaction between these two compounds. The balanced equation for the conversion of C6H12O6 to C2H5OH is C6H12O6 -> 2 C2H5OH. This means that for every mole of C6H12O6, you get 2 moles of C2H5OH. You can then use the molar mass of each compound to convert grams to moles, and then determine the grams of C6H12O6 needed to form 7.50g of C2H5OH.
For this you need the atomic (molecular) mass of C2H5OH. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. C2H5OH= 46.1 grams1.271 grams C2H5OH / (46.1 grams) = .0276 moles C2H5OH
Seven!
There are three different elements in ethyl alcohol (C2H5OH): carbon, hydrogen, and oxygen.
The mass of 2 moles of ethyl alcohol would be 92,14 grams.
Seventeen
7.64 days
800 g oxygen are needed.
1 kilogram = 1000 grams. Now you have the means to derive the required answer yourself.
1 kilogram = 1000 grams. You now have all the information required to answer this and similar questions.
160...cant quite grasp HOW though
There are 2 carbon-carbon bonds and 4 carbon-hydrogen bonds in C2H5OH (ethanol).