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If by "o" you mean oxygen, as written by someone not only to lazy to type out the full answer but also even bring themselves to press the shift key, and by "mass" you mean the German unit of measurement written; "Maß"
and pronounced "mass", as is the only possible solution I can think of with that phrasing, then the answer can be found as such:
One
Maß
is equal to one liter.
At standard pressure and temperature a mole of a gas occupies 22.4 liters. Therefore via 1/22.4=
4.46*10^-2 (To three significant figures).
So we have 4.46*10^-2 moles of oxygen, and we just have to convert this to grams. The only problem is that you have said a mass of "o" "atoms" and oxygen gas is diatomic. I shall choose to ignore this poor phrasing and assume you meant oxygen gas. (And solid oxygen could not work either, as it is also a polyatomic molecule.).
Assuming we are dealing with normal oxygen gas then we can find this out by n=m
/M, or rather 4.46*10^-2=m/32 (oxygen's mass number being 16, and there being two oxygen atoms in a molecule of oxygen gas.) This comes to 1.43 grams.
In summery, a mass of o atoms can have 1.43 grams, but only if it is German and Germany just passed a law preventing the ownership of grams by molecules of O2 and so the O2 molecules have to pretend they are actually having atoms of o instead.
What else can I help you with?
How many grams of N combine with 7.05x1022 O atoms in N2O5?
The formula N2O5 shows that there are 2/5 as many nitrogen atoms as oxygen atoms in the compound. Therefore, the number of nitrogen atoms required is (2/5)(7.05 X 1022) or 2.82 X 1022 atoms. The gram atomic mass of nitrogen is 14.0067 and, by definition, consists of Avogadro's Number of atoms. Therefore, the mass of nitrogen required to react with the specified amount of oxygen to produce the specified compound is 14.0067 [(2.82 X 1022)/(6.022 X 1023] or 0.656 grams of nitrogen, to the justified number of significant digits.
What is the difference between the mass of a mole of oxygen and a mole of O2 molecules?
A mole of oxygen atoms has a mass of approximately 16 grams. A mole of O2 has a mass of approximately 32 grams. A mole is 6.02 x 1023 particles and as such a mole of oxygen atoms has only half the mass of a mole of oxygen molecules.
How many atoms are in sucrose table sugar?
1 mole has 12.01 grams and has 6.022 x 1023 atoms. There are 6 carbon atoms in a glucose molecule so that times six would give you a total of 72.06 grams out of the 180.156 (molar mass for glucose). Carbon makes up about 40 percent of the total glucose mass so the final answer would be it would be around 2.4088 x 1023 atoms of carbon in one gram. Times that by 4 and you'll get 9.6352 x 1023 atoms of carbon in four gram of glucose.
How many atoms of oxygen are there in 698 grams of AlNo33?
Quite a few! 698 grams Al(NO3)3 (1 mole Al(NO3)3/213.01 grams)(9 moles O/1 mole Al(NO3)3)(6.022 X 1023/1 mole O) = 1.78 X 1025 atoms of oxygen ======================
What mass of oxygen in grams is in 147.2 grams of glucose?
To determine the mass of oxygen in 147.2 grams of glucose (C6H12O6), we need to consider the molecular formula of glucose. For each mole of glucose, there are 6 moles of oxygen atoms. The molar mass of glucose is approximately 180.16 g/mol. Thus, the mass of oxygen in 147.2 grams of glucose would be (6/180.16) * 147.2 = approximately 4.88 grams.
What is the mass of one mole atoms?
The mass of one mole of atoms is equal to the atomic mass of the element expressed in grams. This is known as the molar mass. For example, the molar mass of carbon (C) is 12 grams per mole, of oxygen (O) is 16 grams per mole, and so on.
How many grams of N combine with 7.05x1022 O atoms in N2O5?
The formula N2O5 shows that there are 2/5 as many nitrogen atoms as oxygen atoms in the compound. Therefore, the number of nitrogen atoms required is (2/5)(7.05 X 1022) or 2.82 X 1022 atoms. The gram atomic mass of nitrogen is 14.0067 and, by definition, consists of Avogadro's Number of atoms. Therefore, the mass of nitrogen required to react with the specified amount of oxygen to produce the specified compound is 14.0067 [(2.82 X 1022)/(6.022 X 1023] or 0.656 grams of nitrogen, to the justified number of significant digits.
What is the difference between the mass of a mole of oxygen and a mole of O2 molecules?
A mole of oxygen atoms has a mass of approximately 16 grams. A mole of O2 has a mass of approximately 32 grams. A mole is 6.02 x 1023 particles and as such a mole of oxygen atoms has only half the mass of a mole of oxygen molecules.
How many atoms of oxygen are there in 13 grams of water?
There are 7.24 x 10^23 atoms of oxygen in 13 grams of water. This calculation is based on the molar mass of water (18.015 g/mol) and the fact that each water molecule contains two hydrogen atoms and one oxygen atom.
What would you multiply grams of oxygen by to get the units atoms of oxygen?
There is no direct relationship between grams of oxygenand atoms of oxygen. Use the atomic mass to convert grams to moles and Avogadro's number to convert moles to atoms.Since you are converting from grams O, this goes in the denominator (on the bottom) of the first factor. You want to end up in units of atoms of O, so this goes in the numerator (on the top) of the last factor.g O1.00 mole O6.02E+23 atom O= atoms O16.0 gram O1.00 mole ONote that the units grams oxygen "cancel out" in the first factor and you are left in units of moles. Moles cancel out in the second factor and the final units are atoms oxygen.
How many atoms are in sucrose table sugar?
1 mole has 12.01 grams and has 6.022 x 1023 atoms. There are 6 carbon atoms in a glucose molecule so that times six would give you a total of 72.06 grams out of the 180.156 (molar mass for glucose). Carbon makes up about 40 percent of the total glucose mass so the final answer would be it would be around 2.4088 x 1023 atoms of carbon in one gram. Times that by 4 and you'll get 9.6352 x 1023 atoms of carbon in four gram of glucose.
How many grams are there in 1810 atoms of oxygen?
1 mole O = 15.9994g = 6.022 x 1023 atoms 1810 atoms O x 15.9994g/6.022 x 1023 atoms = 4.81 x 10-20g
How many atoms of oxygen are there in 698 grams of AlNo33?
Quite a few! 698 grams Al(NO3)3 (1 mole Al(NO3)3/213.01 grams)(9 moles O/1 mole Al(NO3)3)(6.022 X 1023/1 mole O) = 1.78 X 1025 atoms of oxygen ======================
What mass of oxygen in grams is in 147.2 grams of glucose?
To determine the mass of oxygen in 147.2 grams of glucose (C6H12O6), we need to consider the molecular formula of glucose. For each mole of glucose, there are 6 moles of oxygen atoms. The molar mass of glucose is approximately 180.16 g/mol. Thus, the mass of oxygen in 147.2 grams of glucose would be (6/180.16) * 147.2 = approximately 4.88 grams.
How many atoms are in 16.00 g of O?
Since the atomic weight of oxygen is 15.9994 or 15.9994 grams/mole 16.00 grams of O would be 1.000 moles. 1 mole of something contains Avogadro's number (6.0221415 × 1023 mol-1) of particles of that substance - in this case atoms so 16.00 grams of O would be 6.0221415 × 1023 atoms of O.
How many atoms are in 16 grams of oxygen?
1mol O = 16.0g (rounded to 1 decimal place) 1mol O atoms = 6.022 x 1023 atoms 16g O x 1mol/16g = 1mol O 1mol O x 6.022 x 1023atoms/mol = 6.022 x 1023 atoms O
How many grams of v203 would you need to have 7.56e11 atoms of oxygen?
To determine the grams of V2O3 needed, we first find the number of moles of oxygen atoms in 7.56e11 atoms. Then, using the molar ratio in V2O3 (2 moles of oxygen for every mole of V2O3), we find the moles of V2O3. Finally, we convert moles to grams using the molar mass of V2O3.
