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Molarity = moles of solute/liters of solution

1/10^pH = Molarity ( or 10^ - pH )

= 1 X 10^-4 M

----------------------

find moles CH3COOH

moles of solute = 1 X 10^-4 M/3.4 liters

= 2.94 X 10^-5 moles CH3COOH (60.052 grams/1 mole CH3COOH)

= 0.0018 grams CH3COOH needed

------------------------------------------------- ( 1.8 X 10^- 3 grams )

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This is a calculation of the concentration of acetic acid (CH3COOH). To find the concentration, you divide the moles of CH3COOH by the volume of water in liters. So, the concentration would be 4.32 x 10^2 moles / 20.0 liters = 21.6 moles/liter.


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