The solubility of lead(II) nitrate, Pb(NO3)2, in water is approximately 53.0 grams per 100 mL at room temperature. Therefore, you can dissolve about 53 grams of Pb(NO3)2 in 100 mL of water. Always check specific solubility data as it can vary with temperature.
The solubility of cerium(III) iodate (Ce(IO3)4) in water is approximately 1.5 g/100 mL at room temperature. So, approximately 1.5 grams of Ce(IO3)4 can dissolve in 100 mL of water.
100 ml of pure water under standard conditions has 100 grams of mass. Consequently, on Earth, it weighs 0.98 newtons (about 3.53 ounces).
At 10°C, the solubility of strontium bromide (SrBr₂) in water is approximately 3.5 grams per 100 grams of water. This means that you can dissolve about 3.5 grams of strontium bromide in 100 grams of water at this temperature.
If the solubility of a substance in water is 40 grams per 100 grams of water, this means that in 50 grams of water, you can dissolve half of that amount. Therefore, the maximum amount of solute you can dissolve in 50 grams of water is 20 grams.
400
Approximately 161 grams of lead nitrate will dissolve in 100mL of cold water at room temperature.
100ml
204g of sugar is the maximum amount of sugar that will dissolve into 100mL of water.
To make a 100ml 1M solution of Sodium Chloride, you would dissolve 5.85 grams of NaCl in enough water to make 100ml of solution. This molarity calculation is based on the molar mass of NaCl (58.44 g/mol).
Radium sulphate (RaSO4) is very insoluble in water, more insoluble than the barium sulphate. The solubility product constant of radium sulphate is 3,66.10-11.
The solubility of NaCl at room temperature is 359g/L. (Wikipedia)To find out how much will dissolve in 100mL, first convert 359g/L to g/mL.359g/L x 1L/1000mL = 0.359g/mLThen multiply 0.359g/mL by 100mL0.359g/mL x 100mL = 35.9gYou should expect 35.9 grams of NaCl to dissolve in 100mL of water.
The solubility of cerium(III) iodate (Ce(IO3)4) in water is approximately 1.5 g/100 mL at room temperature. So, approximately 1.5 grams of Ce(IO3)4 can dissolve in 100 mL of water.
100ml of water weighs approximately 100 grams. Adding 15 grams of salt would bring the total weight to 115 grams.
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To make a 10% sugar solution you need to dissolve 10 grams of sugar and bring the volume up to 100 ml
To prepare a 2% solution of ferric chloride in 100ml of water, you would need to add 2 grams of ferric chloride. This is calculated by multiplying the volume of the solution (100ml) by the desired concentration (2%) and converting it to grams.
Phthalic acid will dissolve 18g of per 100mL of boiling water. (25g/18g) x 100mL = 138.89mL of boiling water is needed to dissolve 25g of phthalic acid.