The chemical equation for the preparation of acetaldehyde from ethylene is:
C2H4 + O2 -> CH3CHO
By stoichiometry, 1 mol of ethylene produces 1 mol of acetaldehyde. So, calculate the number of moles of ethylene in 81.7 g and use this to determine the grams of acetaldehyde produced.
To determine the grams of ethylene needed to react with 0.0126 mole of water, you need to use the balanced chemical equation for the reaction between ethylene and water. Once you have the balanced equation, use the molar ratio between ethylene and water to convert moles of water to moles of ethylene. Then, use the molar mass of ethylene to convert moles of ethylene to grams of ethylene.
63 g of water are needed.
Sodium sulfate is not prepared from hydrogen chloride.
To react with 0.373 mol of ethylene (C2H4), you need an equal number of moles of water (H2O) based on the balanced chemical equation: C2H4 + H2O → C2H5OH This means you need 0.373 mol of water to react with 0.373 mol of ethylene. To convert moles to grams, you would multiply 0.373 mol by the molar mass of water (18.015 g/mol) to get the grams needed.
Ethylene (C2H4) has two carbons and four hydrogens making 6 atoms.
To determine the grams of ethylene needed to react with 0.0126 mole of water, you need to use the balanced chemical equation for the reaction between ethylene and water. Once you have the balanced equation, use the molar ratio between ethylene and water to convert moles of water to moles of ethylene. Then, use the molar mass of ethylene to convert moles of ethylene to grams of ethylene.
63 g of water are needed.
If ethylene (C2H4) undergoes complete combustion, it will react with oxygen to produce carbon dioxide and water. The balanced chemical equation for the combustion of ethylene is: C2H4 + 3 O2 → 2 CO2 + 2 H2O. Since 1 mol of C2H4 produces 2 mol of CO2, the molar ratio is 1:2. Therefore, starting with 45 grams of ethylene, it will result in 120 grams of carbon dioxide being produced.
It would depend how it was prepared- that would change the number drastically.
Sodium sulfate is not prepared from hydrogen chloride.
To react with 0.373 mol of ethylene (C2H4), you need an equal number of moles of water (H2O) based on the balanced chemical equation: C2H4 + H2O → C2H5OH This means you need 0.373 mol of water to react with 0.373 mol of ethylene. To convert moles to grams, you would multiply 0.373 mol by the molar mass of water (18.015 g/mol) to get the grams needed.
5000 grams and a little cinnamon
ask Bill Nye
Try asking Google
Oh, dude, preparing oxalic acid from ethylene involves a series of chemical reactions that I'm sure some chemistry whiz out there can explain in detail. Basically, you start by oxidizing ethylene to ethylene glycol, then oxidize that to oxalic acid. It's like a chemistry magic show, but with less rabbits and more safety goggles.
C2H4 + H2O --> C2H5OHReaction balanced at 1:1:1 mole of each compound, so you'll need 0.132 mol C2H4 and this is equal to:0.132 (mol C2H4) * 28 (g/mol C2H4) = 3.696 g C2H4 = 3.70 g C2H4
Ethylene (C2H4) has two carbons and four hydrogens making 6 atoms.