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How many grams of ammonium sulfate are needed to make a 0.25 molar solution at a concentration of 6 molar?
To prepare a 0.25 M solution of ammonium sulfate (NH₄)₂SO₄, you first need to determine the molar mass of ammonium sulfate, which is approximately 132.14 g/mol. For a 0.25 M solution, you need 0.25 moles per liter. Therefore, to make 1 liter of a 0.25 M solution, you would need 0.25 moles × 132.14 g/mol = 33.04 grams of ammonium sulfate. If you want to prepare a solution at a concentration of 6 M instead, you would need a significantly higher amount, specifically 6 moles × 132.14 g/mol = 792.84 grams for 1 liter.
How many grams of nitrogen and phosphorus are available in 1.00 pound of ammonium phosphate?
There is said to be about 600 grams of nitrogen in 1.00 pound of ammonium and 130 pounds of phosphorus available in 1.00 pounds of ammonium phosphate.
How many grams of ammonium chloride are contained in 0.500?
For 0,5 mol the answer is 26,745 g.
1 liter equals how many grams?
The conversion from liters to grams depends on the substance being measured, as the density varies across different substances. To determine the number of grams in 1 liter, you will need to know the density of the specific substance in grams per liter. Once you have the density, you can multiply it by 1 liter to find the equivalent weight in grams.
How many grams of honey are in a twenty liter jerrycan?
25000
How many grams per liter ammonium sulfate are in a saturated solution of ammonium sulfate?
Approximately 770 grams of ammonium sulfate can dissolve in one liter of water to form a saturated solution at room temperature.
How many you hydrogen atms are present in onemoecule of ammonium acetate NH4C2H3O2?
There are 4 hydrogen atoms in one molecule of ammonium acetate (NH4C2H3O2).
How many hydrogen atoms are present in one molecule of ammonium acetate?
7
How many milliliters of an aqueous solution of 0.149 M ammonium acetate is needed to obtain 16.9 grams of the salt?
To find the amount of solution, we first determine the number of moles in 16.9 g of ammonium acetate. Then, we use the molarity to calculate the volume of the solution needed. Finally, we convert the volume from liters to milliliters.
How many hydrogen atoms are in one molecule of ammonium acetate NH4C2H3O2?
There are 7 hydrogen atoms. Because 4+3 is 7
How many c atoms in ammonia acetate?
Ammonium acetate does not contain any carbon atoms. It is composed of nitrogen, hydrogen, and oxygen atoms.
985 grams of ethyl acetate equals how many liters?
To convert grams to liters, you need to know the density of ethyl acetate, which is approximately 0.902 grams per milliliter. Therefore, 985 grams of ethyl acetate is equivalent to approximately 1.09 liters.
How do you prepare 1 normality ammonium acetate solution?
A normal solution contains 1 equivalent mass, in grams, of the solute in 1 litre of solution. Firstly, you calculate the mole mass of ammonium acetate. (77g). Weigh this out in a small, clean beaker. Add de-ionized water to dissolve the solid, then transfer the solution to a 1 litre volumetric flask, remembering to wash out the beaker three times with small volumes of de-ionized water, and add the washings to the volumetric flask. Similarly rinse the glass rod with small volumes of the water into the flask. Now add de-ionized water to the 1 litre mark and then mix the solution thoroughly by inverting the stoppered flask many times. Normality is not used much any more, molarity is more usual, though for this solid the two happen to be the same. Ammonium acetate has the systematic name ammonium ethanoate.
129 grams per liter is equal to how many micro grams per liter?
129 (grams per liter) = 129,000,000 micrograms per liter.
How many grams of ammonium sulfate are needed to make a 0.25 molar solution at a concentration of 6 molar?
To prepare a 0.25 M solution of ammonium sulfate (NH₄)₂SO₄, you first need to determine the molar mass of ammonium sulfate, which is approximately 132.14 g/mol. For a 0.25 M solution, you need 0.25 moles per liter. Therefore, to make 1 liter of a 0.25 M solution, you would need 0.25 moles × 132.14 g/mol = 33.04 grams of ammonium sulfate. If you want to prepare a solution at a concentration of 6 M instead, you would need a significantly higher amount, specifically 6 moles × 132.14 g/mol = 792.84 grams for 1 liter.
How many grams of nitrogen and phosphorus are available in 1.00 pound of ammonium phosphate?
There is said to be about 600 grams of nitrogen in 1.00 pound of ammonium and 130 pounds of phosphorus available in 1.00 pounds of ammonium phosphate.
How many grams of ammonium chloride can dissolve in 100g of water at 50 c?
Approximately 37 grams of ammonium chloride can dissolve in 100g of water at 50°C.
