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How many kilo joules of energy are needed to boil 90 grams of water at its boiling point?
To calculate the energy needed to boil 90 grams of water, we use the formula ( q = m \cdot L ), where ( q ) is the heat energy, ( m ) is the mass of the water, and ( L ) is the latent heat of vaporization for water, which is approximately 2260 kJ/kg. For 90 grams (0.09 kg), the calculation is ( q = 0.09 , \text{kg} \cdot 2260 , \text{kJ/kg} ), resulting in about 203.4 kJ of energy needed to boil the water.
How many grams of H2O are needed to react with 3.5 moles of ethylene?
63 g of water are needed.
How many joules are needed to change 219.70 g of water at 72.7 C to steam at 100 C?
This value is 22,418 kJ.
How many joules of energy are needed to heat steam from 100 celsius to 114 celsius?
Approx 2940 Joules.
How many grams of CH3OH is needed to make 0.211m solution in 479g of water?
The answer is 3,211 g.
How many joules are needed to warm 25.5 grams of water from 14.0C to 22.5C?
9.1x10^2J
How many joules of heat are needed to completely vaporize 24.40 grams of water at its boiling point?
The heat of vaporization of water is 40.79 kJ/mol. First, determine the number of moles in 24.40 grams of water. Then, convert moles to joules using the molar heat of vaporization. This will give you the amount of heat needed to vaporize 24.40 grams of water.
How many joules are in 1500 grams?
Voltage is electrical pressure and Joules is a power rating so other info is needed
How many grams is equals 1 joules?
0000000000000000.11 joules
How many joules are necessary to heat a sample of water with a mass of 46.0 grams from 0.0?
46 calories (or 192, 464 joules) for each Celsius degree.
How many joules are needed to change the temperature of 1 gram of water by 1C?
It takes 4.184 joules of energy to change the temperature of 1 gram of water by 1 degree Celsius.
How many joules of heat are needed to raise the temp of 2.83 kg of water from 38C to 46C?
0.0796
How many kilo joules of energy are needed to boil 90 grams of water at its boiling point?
To calculate the energy needed to boil 90 grams of water, we use the formula ( q = m \cdot L ), where ( q ) is the heat energy, ( m ) is the mass of the water, and ( L ) is the latent heat of vaporization for water, which is approximately 2260 kJ/kg. For 90 grams (0.09 kg), the calculation is ( q = 0.09 , \text{kg} \cdot 2260 , \text{kJ/kg} ), resulting in about 203.4 kJ of energy needed to boil the water.
How many grams of water are needed to produce one hundred fifty grams of magnesium hydroxide?
A lot
How many grams of H2O are needed to react with 3.5 moles of ethylene?
63 g of water are needed.
How many joules are needed to change 219.70 g of water at 72.7 C to steam at 100 C?
This value is 22,418 kJ.
How many joules are absorbed by the water with a mass of 8 kg in order to raise the temperature from 20 degrees to 70 degrees?
q(joules) = mass * specific heat * change in temperature ( 8 kg = 8000 grams ) q = (8000 grams H2O)(4.180 J/gC)(70o C - 20o C) = 1.7 X 106 joules ============
