This heat is 32,48 joules.
The energy required to melt ice is known as the heat of fusion, which is about 334 joules per gram. Therefore, it would take approximately 3340 joules of energy to melt 10g of ice.
Heat required to melt 1 g of ice at 0°C is approximately 80 cal . This is also called latent heat of fusion of ice.
334 j/g =167000 j
The necessary heat is 9,22 joules.
This heat is 32,48 joules.
The heat required to melt ice is called the heat of fusion, which is 334 J/g. To melt 500g of ice, you would need 334 J/g x 500g = 167000 joules of heat.
The energy required to melt ice is known as the heat of fusion, which is about 334 joules per gram. Therefore, it would take approximately 3340 joules of energy to melt 10g of ice.
In order to answer this question, you need the enthalpy of fusion of ice, which is 333.55 J/g (Joules/gram). The enthalpy of fusion is the amount of heat that must be absorbed or lost in order to change physical state. The number of Joules required to melt the ice = enthalpy of fusion of ice x mass of ice. Joules needed to melt the ice = 333.55 J/g x 40 g = 13342 J
In order to answer this question, you need the enthalpy of fusion of ice, which is 333.55 J/g (Joules/gram). The enthalpy of fusion is the amount of heat that must be absorbed or lost in order to change physical state. The number of Joules required to melt the ice = enthalpy of fusion of ice x mass of ice. 1 kg = 1000g 40kg x (1000g/1kg) = 40,000g Joules needed to melt the ice = 333.55 J/g x 40000 g = 13342000 J or 1.3342 x 107 J
Heat required to melt 1 g of ice at 0°C is approximately 80 cal . This is also called latent heat of fusion of ice.
The heat of fusion of water, which is the amount of heat energy required to melt one gram of ice at its melting point, is approximately 334 joules per gram. This means that to melt an ice cube, the ice must absorb 334 joules of heat energy per gram to transition from a solid to a liquid state.
The amount of energy required to melt ice is given by the formula Q = m * L, where Q is the energy in joules, m is the mass in grams, and L is the heat of fusion for ice (334 J/g). Plugging in the values, we find that it would take 12.8 g * 334 J/g = 4288 joules to melt 12.8 g of ice at 0°C.
The heat required to melt 5 kg of ice is 334,750 J. This is calculated using the formula Q = m * Lf, where Q is the heat energy (Joules), m is the mass of the substance (kg), and Lf is the specific latent heat of fusion for ice (334,750 J/kg).
The total energy required to melt ice at 0°C to liquid water at 0°C is known as the heat of fusion. For water, the heat of fusion is 334 J/g. Therefore, to melt 100 grams of ice, you would need 100 grams * 334 J/g = 33400 Joules of energy.
The energy required to melt a substance
334 j/g =167000 j