On average, a fan oven typically uses between 2-3 kWh per hour when in use. This can vary depending on the temperature setting and cooking time.
To calculate the cost of using an electric oven for 1.5 hours, you need to know its wattage and your electricity rate. For example, if the oven uses 3,000 watts (or 3 kWh) and your electricity rate is $0.12 per kWh, the cost would be 3 kWh × $0.12 = $0.36. Thus, using the oven for 1.5 hours would cost approximately $0.36. Adjust the wattage and rate as necessary for accurate calculations.
In ten hours, a 200W bulb will use: 10 * 200 = 2000 Watt-hours = 2 kwh
The fan has a rated load of 2 kW. It is this wattage times the amount of hours the fan is used times the cost of a kWh in your area that the cost is based on.
It depends on the btu of the unit
About 11.75 cents per kWh for residential use (7.53 cents/kWh for industrial), as of September 2010:
none, if it is unplugged
That depends on the type and make of Oven.
The energy consumption of an electric fan typically ranges from about 40 to 100 watts per hour, depending on its size and speed settings. To convert this to kilowatt-hours (kWh), divide the wattage by 1,000. For example, a 75-watt fan would use 0.075 kWh per hour. Thus, the exact usage can vary, but it generally falls within this range.
100 kWh
To calculate the cost of using an electric oven for 1.5 hours, you need to know its wattage and your electricity rate. For example, if the oven uses 3,000 watts (or 3 kWh) and your electricity rate is $0.12 per kWh, the cost would be 3 kWh × $0.12 = $0.36. Thus, using the oven for 1.5 hours would cost approximately $0.36. Adjust the wattage and rate as necessary for accurate calculations.
Look on the manufactures label on the fan. Find the amperage and voltage of the device. Multiply these two values together to find the wattage of the device. If the fan operates 24 hours a day, take the wattage and multiply it by the wattage of the fan. This will give you the total wattage that the fan will use in a day. To take it a step further take the total and divide it by 1000 and this will give you the kWh the fan uses. Find out what you are charged by the utility company and multiply the kWh by this number. This will tell you how much it costs to operate the fan for a 24 hour period.
You can do this in either a conventional or a convection oven. If you use a conventional oven, I would rotate the roasting pan half way through the cooking process to compensate for any hot spots in the oven. If you use a convection oven (with the fan), cooking is more even because the fan blows the hot air around the food, but you have to remember to reduce cooking temperatures 50 degrees if you leave the convection function on.
10 amps at 120 volts is 1200 watts or 1.2 Kw, so in 1 hour it will use 1.2 Kwh
In ten hours, a 200W bulb will use: 10 * 200 = 2000 Watt-hours = 2 kwh
Generally you deduct temperature not time for a fan assisted oven. For a recipe saying 200o use 180o on a fan assisted. Obviously all ovens are different but this should work.
The fan has a rated load of 2 kW. It is this wattage times the amount of hours the fan is used times the cost of a kWh in your area that the cost is based on.
To convert 290 degrees Fahrenheit to a fan oven setting in Celsius, you can use the formula: (F - 32) × 5/9 = C. This calculation results in approximately 143 degrees Celsius. In a fan oven, it’s typically recommended to reduce the temperature by about 20 degrees Celsius, so you might set your fan oven to around 120-125 degrees Celsius for optimal results.