How many kinds of gametes will be formed for genotype AaBCcDdEe?

Answer 1

To determine the number of different gametes formed from the genotype AaBCcDdEe, we consider the alleles at each gene locus. The genotype has 5 loci: A (2 options: A or a), B (1 option: B), C (2 options: C or c), D (2 options: D or d), and E (2 options: E or e). The total number of gametes can be calculated using the formula (2^n), where (n) is the number of heterozygous loci. In this case, there are 4 heterozygous loci (A, C, D, and E), so the number of different gametes is (2^4 = 16).