Water itself does not contain kilojoules (kJ) as it has no caloric value. However, when considering the energy required to heat water, for example, one can calculate the energy in kilojoules based on its mass and the temperature change using the specific heat capacity of water, which is approximately 4.18 kJ/kg°C. Thus, the energy content depends on the context in which the water is being used or heated.
10,267 kJ are needed
The heat required to vaporize 5.00 g of water is given by: 2260 J/g * 5.00 g = 11300 J. Converting this to kJ gives 11.3 kJ.
There are approximately 560 kJ in 4 Weetbix biscuits.
2,26 Kj are necessary
The heat released when 3.600 mol of NaOH is dissolved in water will depend on the enthalpy change of the dissolution process. This value is typically around -44 kJ/mol for NaOH in water. Therefore, the total heat released would be -44 kJ/mol * 3.600 mol = -158.4 kJ.
The reaction of lithium and water produces 286 kJ/mol of lithium.
10,267 kJ are needed
1000 kj, kj means thousand Jules.
8,000 to 10,000 kJ.
To convert latent heat of condensation from kJ/kg to kJ/m^3, you need to consider the density of water. The density of water is approximately 1000 kg/m^3. So, multiply the latent heat of condensation (334 kJ/kg) by the density of water (1000 kg/m^3) to get the heat in kJ/m^3, which would be 334,000 kJ/m^3.
350 kJ is 83.6 calories.
3.97 kJ = 0.95 calories.
8700 kJ is 2,077.96 calories.
485 kJ is about 116 calories.
kj
About 1/4 of a calorie per kJ
The amount of energy given off when 17.0 mol of water is frozen can be calculated by multiplying the number of moles by the heat of fusion. Energy = 17.0 mol * 6.01 kJ/mol = 102.17 kJ.