22.4litres
A 0.50 mole sample of helium will occupy a volume of 11.2 liters under standard temperature and pressure (STP) conditions, which are 0 degrees Celsius (273.15 K) and 1 atmosphere pressure. At STP, one mole of any gas occupies a volume of 22.4 liters.
one mole of He
Lead. The molar mass of lead is 207.2 g/mol while helium's is 4.0 g/mol.
At standard atmospheric pressure (1 atm) and a temperature of 273.15 K (0°C), one mole of helium gas occupies approximately 22.4 liters. This volume is consistent with the ideal gas law, which states that under these conditions, gases behave ideally. Therefore, the volume of one mole of helium gas at these conditions is about 22.4 L.
By definition, one mole would be the same as the atomic mass. You take the number of moles and multiply it by the atomic mass (divide by one mole for units to cancel). So if you have just 1 mole, the number of grams will be the atomic mass. Helium's atomic mass is 4.003 grams.
A 0.50 mole sample of helium will occupy a volume of 11.2 liters under standard temperature and pressure (STP) conditions, which are 0 degrees Celsius (273.15 K) and 1 atmosphere pressure. At STP, one mole of any gas occupies a volume of 22.4 liters.
No, 1 mole of hydrogen atoms does not equal 1 mole of helium atoms. One mole of any element contains Avogadro's number of atoms (6.022 x 10^23), so 1 mole of hydrogen atoms would have that many hydrogen atoms, while 1 mole of helium atoms would have that many helium atoms.
one mole of He
Lead. The molar mass of lead is 207.2 g/mol while helium's is 4.0 g/mol.
At standard atmospheric pressure (1 atm) and a temperature of 273.15 K (0°C), one mole of helium gas occupies approximately 22.4 liters. This volume is consistent with the ideal gas law, which states that under these conditions, gases behave ideally. Therefore, the volume of one mole of helium gas at these conditions is about 22.4 L.
the first inoization energy is 2372.3 kJ mol-1 there are 6.0221415 × 10^23 in a mole from avagadros number, devide the ionization energy for one mole by the number of atoms in a mole and you get the first ionization energy for one atom.
Not sure what you mean by "first letter is a c", but the volume of one mole of an ideal gas at STP is 22.4 Liters.
By definition, one mole would be the same as the atomic mass. You take the number of moles and multiply it by the atomic mass (divide by one mole for units to cancel). So if you have just 1 mole, the number of grams will be the atomic mass. Helium's atomic mass is 4.003 grams.
At standard temperature and pressure (STP), one mole of any ideal gas occupies 22.4 liters. To find the number of moles of ammonia gas (NH₃) required to fill a volume of 50 liters, you can use the formula: moles = volume (liters) / volume per mole (liters/mole). Therefore, the calculation is 50 liters / 22.4 liters/mole = approximately 2.24 moles of NH₃ are needed.
The number of atoms in one mole of any substance is defined by Avogadro's number, which is approximately (6.022 \times 10^{23}) entities per mole. However, when comparing hydrogen and helium, it's essential to note that hydrogen exists as diatomic molecules (H₂) in its natural state, meaning one mole of hydrogen gas contains (6.022 \times 10^{23}) molecules, each consisting of 2 atoms, resulting in (2 \times 6.022 \times 10^{23}) atoms. In contrast, helium is a monatomic gas, so one mole of helium contains (6.022 \times 10^{23}) atoms. Thus, the total number of atoms in one mole of hydrogen is twice that of one mole of helium.
At standard temperature and pressure (STP), one mole of gas occupies 22.4 liters. To find the number of moles in 15.7 liters of chlorine gas, divide 15.7 liters by 22.4 liters/mole, which gives approximately 0.699 moles. Since one mole contains Avogadro's number of molecules (approximately (6.022 \times 10^{23}) molecules/mole), the total number of molecules is about (0.699 \times 6.022 \times 10^{23} \approx 4.21 \times 10^{23}) molecules.
One mole of any gas at STP occupies 22.4 liters. Therefore, one mole of oxygen gas at STP also occupies 22.4 liters.