Suppose 25 L to be 25 kg water (almost, -0.2% at room temperature)
then divide 25,000 g by the moalr mass of H2O being 2+16=18 g/mole
you get = 1385 moles (because 1 mole = 18 grams)
1,67.1024 argon atoms is equal to 2,773 moles.
To find the mass of argon in grams for 100 moles, you can use the molar mass of argon, which is approximately 40 grams per mole. Therefore, the mass of 100 moles of argon would be calculated as follows: 100 moles × 40 g/mole = 4000 grams. Thus, there are 4000 grams of argon in 100 moles.
8,4 liters of nitrous oxide at STP contain 2,65 moles.
To find the number of moles of argon in 160 grams, you can use the molar mass of argon, which is approximately 40 g/mol. Using the formula: [ \text{Number of moles} = \frac{\text{mass (g)}}{\text{molar mass (g/mol)}} ] we can calculate: [ \text{Number of moles} = \frac{160 \text{ g}}{40 \text{ g/mol}} = 4 \text{ moles} ] Thus, there are 4 moles of argon in 160 grams.
Molarity = moles of solute/Liters of solution 3.42 M NaOH = 1.3 moles NaOH/Liters NaOH Liters NaOH = 1.3 moles NaOH/3.42 M NaOH = 0.38 Liters
There are 0.25 moles of argon gas present in 5.6 liters at standard conditions (1 mole of any gas occupies 22.4 liters at standard conditions).
1,67.1024 argon atoms is equal to 2,773 moles.
To find the number of moles of argon in 37.9 g, you need to use the molar mass of argon, which is 39.95 g/mol. Divide the given mass by the molar mass to get the number of moles. So, 37.9 g / 39.95 g/mol = 0.95 moles of argon.
At STP, 1 mole of any gas occupies 22.4 L. Therefore, in a 5L sample of argon at STP, there would be 5/22.4 moles of argon, which is approximately 0.223 moles.
55.64
Have: 607gAr Need: Moles of Argon From the periodic table we know that there are 39.948gAr per every 1 mole of Argon. 607g/39.948 = your answer.
There are 0.639 moles in 28.85 grams of Argon. This is calculated by dividing the given mass by the molar mass of Argon which is approximately 39.95 g/mol.
To find the mass of argon in grams for 100 moles, you can use the molar mass of argon, which is approximately 40 grams per mole. Therefore, the mass of 100 moles of argon would be calculated as follows: 100 moles × 40 g/mole = 4000 grams. Thus, there are 4000 grams of argon in 100 moles.
1 mole occupies 22.414 liters So, 1.84 moles will occupy 41.242 liters
To find the number of moles, divide the given mass of argon by its molar mass. The molar mass of argon is approximately 39.95 g/mol. Number of moles of argon = 14.5 g / 39.95 g/mol Number of moles of argon = 0.362 moles
To find the number of moles of argon in 24.7 g, you need to divide the mass of the sample by the molar mass of argon (39.95 g/mol). Therefore, 24.7 g of argon is equal to 0.62 moles (24.7 g ÷ 39.95 g/mol = 0.62 mol).
To find the number of moles in 15.01 grams of argon, you need to divide the given mass by the molar mass of argon. The molar mass of argon is approximately 39.95 g/mol. So, the number of moles of argon in 15.01 grams would be 15.01 g / 39.95 g/mol = 0.376 moles.