1 mole = 20.18 g of Neon = 6.023 x 1023 atoms of neon (A neon molecule has only one atom)
So, 39 moles = 39 x 6.023 x 1023 atoms = 234.897 x 1023 atoms of neon
KCl has a molar mass of 39+35.5=74.5g/mol, and 48/74.5=0.64mol.
2C6H6 + 15O2 ==> 12CO2 + 6H2Omoles C6H6 combusted = 45.0 g x 1 mole/78 g = 0.577 molesmoles CO2 formed = 0.577 moles C6H6 x 12 moles CO2/2 moles C6H6 = 3.46 moles CO2
In the process of photosynthesis, 6 molecules of carbon dioxide react with 6 molecules of water to form one molecule of glucose and 6 molecules of oxygen. Thus, 12 molecules of hydrogen are required to form one molecule of glucose (from the 6 molecules of water).
The atomic mass of Potassium is 39 and that of Sulfur 32. The formula for Potassium Sulfide is K2S therefore the molecular weight of Potassium Sulfide is (39 * 2) + 32 = 110. Therefore one mole of Potassium Sulfide weighs 110 grams. Therefore 3.3 moles of Potassium Sulfide weigh 110 * 3.3 = 363 grams.
how many grams is 39cc?
KCl has a molar mass of 39+35.5=74.5g/mol, and 48/74.5=0.64mol.
78
Steam is just water. Water weighs the same per molecule regardless whether it is ice, water, or steam. That said, the molecular weight of water is right at 18 g/mole. So it seems that 9.0 grams of steam is about half a mole of water. Therefore we just divide avagrado's number by 2 and we get: 6.022 x 1023 / 2 = 3.011 x 1023 molecules
39 grams of lead is equivalent to approximately 0.36 moles of lead.
To determine the number of moles of potassium in 449 g, you need to divide the mass (449 g) by the molar mass of potassium (39.1 g/mol). This calculation would give you the number of moles of potassium in 449 g.
2C6H6 + 15O2 ==> 12CO2 + 6H2Omoles C6H6 combusted = 45.0 g x 1 mole/78 g = 0.577 molesmoles CO2 formed = 0.577 moles C6H6 x 12 moles CO2/2 moles C6H6 = 3.46 moles CO2
In the process of photosynthesis, 6 molecules of carbon dioxide react with 6 molecules of water to form one molecule of glucose and 6 molecules of oxygen. Thus, 12 molecules of hydrogen are required to form one molecule of glucose (from the 6 molecules of water).
This depends on the specific recipe of a producer.
To find the amount of oxygen required for the combustion of liquid benzene, you would need to balance the combustion reaction equation for benzene. Calculate the moles of benzene from the given mass, then use the stoichiometry of the balanced equation to determine the moles of oxygen required. Finally, convert the moles of oxygen to liters using the ideal gas law.
There are 39.0983 grams in one mole of K (potassium). a mole is a number. you cannot ask how many moles are in potassium. but you may ask how many moles of a certain substance are in potassium.
39
There are 39 inches in 39 inches.