7,224.10e24. hydrogen atoms
If it is 1.54 moles of Br atoms then the answer is 9.274 X 1023 atoms.If it is 1.54 moles of Br2 molecules then the answer is 1.855 X 1024 atoms.
1 x 1024 molecules
4,96 x 1024 molecules of glucose is equal to 8,236 moles.
Boron atoms have 5 protons. You can derive this from the periodic table because the atomic number is the amount of protons the nucleus of an atom contains.
There is one boron atom in one molecule of BF3.
To calculate the number of atoms in 15.8 moles of boron, you can use Avogadro's number, which is 6.022 x 10^23 atoms/mole. Multiply 15.8 moles by Avogadro's number to get approximately 9.5 x 10^24 atoms of boron.
2
There are 4 boron atoms in a molecule of borax, which has the chemical formula Na2B4O7·10H2O.
7,224.10e24. hydrogen atoms
there are 5 electrons in boron atoms.
If it is 1.54 moles of Br atoms then the answer is 9.274 X 1023 atoms.If it is 1.54 moles of Br2 molecules then the answer is 1.855 X 1024 atoms.
Boron dioxide would have formula BO2, with a total of three atoms, BUT this is NOT a possible compound.B2O3, with 5 atoms, is called boron trioxide (or diboron trioxide, boron oxide, boron sesquioxide, boric oxide alternatively).
1 x 1024 molecules
To calculate the number of grams of fluorine in 5 molecules of boron trifluoride, you need to first determine the molar mass of boron trifluoride (BF3). Boron trifluoride has one boron atom and three fluorine atoms, so the molar mass is ~ 67.8 g/mol. Since each molecule of boron trifluoride contains three fluorine atoms, the total mass of fluorine in 5 molecules would be 3 times the molar mass of fluorine (approximately 19.0 g/mol) times 5.
4,96 x 1024 molecules of glucose is equal to 8,236 moles.
Boron atoms have 5 protons. You can derive this from the periodic table because the atomic number is the amount of protons the nucleus of an atom contains.