0,125 L neon is equivalent to 0,0056 moles.
moles KCL = ( M solution ) ( L of solution )moles KCl = ( 0.83 mol KCl / L ) ( 1.7 L ) = 1.41 moles KCl
The answer is 14,93 moles.
moles KCl = ( M solution ) ( V solution in L )moles KCl = ( 2.2 mol KCl / L solution ) ( 0.635 L of solution )moles KCl = 1.397 moles KCl
The answer is 0,2675 moles.
16,8 L of Xe gas at STP is equivalent to 0,754 moles.
95,474 moles
4,54 L of CO have 0,182 moles.
moles KCL = ( M solution ) ( L of solution )moles KCl = ( 0.83 mol KCl / L ) ( 1.7 L ) = 1.41 moles KCl
Molarity is moles of solute per L of solution.moles KCl = ( 1.68 M ) ( 0.121 L ) = ( 1.68 mol/L ) ( 0.121 L )moles KCl = 0.203 moles KCl
The answer is 14,93 moles.
moles KCl = ( M solution ) ( V solution in L )moles KCl = ( 2.2 mol KCl / L solution ) ( 0.635 L of solution )moles KCl = 1.397 moles KCl
To find the number of moles of sodium chloride, you can multiply the volume of the solution by its molarity. moles = volume (L) * molarity moles = 5.08 L * 2.36 mol/L moles = 11.9928 mol Therefore, there are approximately 11.99 moles of sodium chloride in 5.08 L of a 2.36 M solution.
First, calculate the number of moles of NaOH: Moles = Molarity x Volume (L) Convert mL to L: 450 mL = 0.45 L Moles = 0.25 N x 0.45 L = 0.1125 moles of NaOH.
To find the number of moles, first calculate the number of moles of HCl in the 50 mL solution by multiplying the volume (in liters) by the molarity. Volume in liters = 50 mL / 1000 mL/L = 0.05 L Moles = 0.05 L * 6.0 mol/L = 0.3 moles of HCl.
To find the moles of solute, multiply the volume of the solution in liters (1.25 L) by the molarity of the solution (0.75 mol/L). Therefore, the moles of NaNO3 in 1.25 L of 0.75M solution is 0.9375 moles.
The answer is 0,2675 moles.
16,8 L of Xe gas at STP is equivalent to 0,754 moles.